The balanced equation for the reaction between phenol (C6H5OH), sodium hydroxide (NaOH), and iron(III) chloride (FeCl3) is:
C6H5OH + NaOH + FeCl3 → C6H4(OH)Na + FeCl2 + H2O
When sodium chloride reacts with ammonium hydroxide, it forms sodium hydroxide and ammonium chloride. The balanced chemical equation for this reaction is NaCl + NH4OH -> NaOH + NH4Cl. This is a double displacement reaction where the cations and anions of each compound switch partners.
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
2 NaOH + CuCl2 --> 2 NaCl + Cu(OH)2 (s)
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
It is a neutralisation reaction. The products formed are sodium chloride and water.
Ferric Chloride = FeCl3Ammonium Hydroxide = NH4OHFerric (III) Chloride + Ammonium Hydroxide = Ferric (III) Hydroxide + Ammonium Chloride FeCl3 + 3NH4OH = Fe(OH)3 + 3NH4Cl
When sodium chloride reacts with ammonium hydroxide, it forms sodium hydroxide and ammonium chloride. The balanced chemical equation for this reaction is NaCl + NH4OH -> NaOH + NH4Cl. This is a double displacement reaction where the cations and anions of each compound switch partners.
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
2 NaOH + CuCl2 --> 2 NaCl + Cu(OH)2 (s)
When copper chloride is mixed with sodium hydroxide, a precipitation reaction occurs where solid copper(II) hydroxide is formed. The balanced chemical equation for this reaction is: CuCl2 + 2NaOH → Cu(OH)2 + 2NaCl. This reaction is a double displacement reaction where copper ions and hydroxide ions switch partners to form the solid copper hydroxide.
The balanced equation for the reaction between calcium hydroxide and hydrochloric acid is: Ca(OH)2 + 2HCl → CaCl2 + 2H2O In this reaction, calcium hydroxide (Ca(OH)2) reacts with hydrochloric acid (HCl) to produce calcium chloride (CaCl2) and water (H2O). The equation is balanced with 1 molecule of calcium hydroxide reacting with 2 molecules of hydrochloric acid to produce 1 molecule of calcium chloride and 2 molecules of water.
It is a neutralisation reaction. The products formed are sodium chloride and water.
When ammonium chloride reacts with sodium hydroxide, it undergoes a double displacement reaction where ammonium chloride and sodium hydroxide switch partners to form ammonia, water, and sodium chloride. The balanced chemical equation for this reaction is NH4Cl + NaOH -> NH3 + H2O + NaCl.
Any reaction occur.
When sodium hydroxide is added to ferrous chloride, a precipitation reaction occurs. This results in the formation of insoluble ferrous hydroxide, which appears as a greenish precipitate. The balanced equation for this reaction is: FeCl2 + 2NaOH → Fe(OH)2 + 2NaCl.
Balanced:2 KOH + SO3 ----> K2SO4 + H2O
When sodium hydroxide combines with cadmium chloride, it forms cadmium hydroxide and sodium chloride as products. The balanced chemical equation for this reaction is: 2 NaOH + CdCl2 → Cd(OH)2 + 2 NaCl. Cadmium hydroxide is a white solid that tends to precipitate out of solution.