6.02*10^23atoms (avogadros constant)
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
There are 24 moles of Carbon (C) in 2 moles of table sugar (sucrose)
1 gram carbon (1 mole C/12.01 grams) = 0.08 moles carbon ===============
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
5 moles of carbon is 60,055 g.5 moles of sodium is 114,949 g.
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
211g of carbon dioxide are equal to 4,794 moles.
There are twice as many oxygen atoms as carbon atoms in carbon dioxide, so 100.0 moles of carbon dioxide would contain 200.0 moles of oxygen atoms.
To find the number of moles of carbon (C) in 0.733 moles of C17H21NO, first identify the number of carbon atoms in one molecule of C17H21NO, which is 17. Therefore, the number of moles of carbon can be calculated by multiplying the number of moles of the compound by the number of carbon atoms: 0.733 moles of C17H21NO × 17 moles of C/mole of C17H21NO = 12.441 moles of C. Thus, there are approximately 12.44 moles of carbon present.
There are 9.33 moles of carbon in 5.62 atoms of carbon.
3.5 moles CaCO3 (1 mole carbon/1 mole CaCO3) = 3.5 moles