1 gram carbon (1 mole C/12.01 grams)
= 0.08 moles carbon
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Graphite is a form of carbon, so the question is basically asking how many moles of carbon are in 18.0 grams of carbon. One gram of carbon contains 12.01 moles. This can be found on a periodic table. 18.0 grams of carbon must therefore have 18 times 12.01, or 216.18, moles of carbon.
There are twice as many oxygen atoms as carbon atoms in carbon dioxide, so 100.0 moles of carbon dioxide would contain 200.0 moles of oxygen atoms.
One pound-mole (lbmol) is equivalent to approximately 453.6 gram-moles (gmol).
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
About one half mole. 6 grams carbon (1 mole C/12.01 grams) = 0.4996 moles of carbon --------------------------------- that is, 0.5 moles carbon ---------------------------------
Graphite is a form of carbon, so the question is basically asking how many moles of carbon are in 18.0 grams of carbon. One gram of carbon contains 12.01 moles. This can be found on a periodic table. 18.0 grams of carbon must therefore have 18 times 12.01, or 216.18, moles of carbon.
how many moles are in 95.0 gram of octane?
The answer is 3 moles.
The answer is 0,111 moles.
The formula for methane shows that each molecule of it contains 5 atom: 1 carbon atom and 4 hydrogen atoms. The gram molecular mass of methane is 16.04. Therefore, 28 grams of methane contains 28/16.04 moles of methane and 5 times this number, or 8.7, "moles of atoms", to the justified number of significant digits.
85.2 gram LiF sample is equivalent to 3,28 moles.
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
3.0 moles of H2O have 54 g.
There are twice as many oxygen atoms as carbon atoms in carbon dioxide, so 100.0 moles of carbon dioxide would contain 200.0 moles of oxygen atoms.
27g
211g of carbon dioxide are equal to 4,794 moles.
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