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How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
How many grams of carbon dioxide are produced when 7.5 grams of sodium carbonate reacts with nitric acid?
First write the balance equation: Na2CO3 + 2HNO3 ==> 2NaNO3 + CO2 + H2O Next calculate moles of Na2CO3 used: 7.5 g x 1 mole/106 g = 0.071 moles Na2CO3 Then look at mole ratio of Na2CO3 to CO2 and see that it is 1 to 1 Thus, moles CO2 produced = 0.071 moles Finally, convert moles CO2 to grams of CO2: 0.071 moles x 44g/mole = 3.1 g (to 2 significant figures)
How many moles of carbon dioxide will be formed upon the complete reaction of 22.2 grams of carbon with excess oxygen gas?
Balanced equation. C + O2 -> CO2 22.2 grams carbon (1 mole C/12.01 grams)(1 mole CO2/1 mole C) = 1.85 moles carbon dioxide produced -------------------------------------------------
How many grams of carbon monoxide (CO) are there in 2.55 moles of the ompound?
To determine the mass of carbon monoxide in 2.55 moles, we first find the molar mass of CO, which is 28.01 g/mol. Then, we multiply the molar mass by the number of moles: 28.01 g/mol * 2.55 mol = 71.53 grams of CO in 2.55 moles of the compound.
How many moles of carbon dioxide are there in 19 grams of carbon dioxide?
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
How many moles of carbon are there from the original sample of 11.0 grams of carbon dioxide and 4.50 grams of water with a combustion of 7.50 grams?
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many moles are in 66 grams of carbon dioxide?
To calculate the number of moles in 66 grams of carbon dioxide, we need to divide the given mass by the molar mass of carbon dioxide. The molar mass of carbon dioxide is approximately 44 grams per mole. Therefore, 66 grams of carbon dioxide is equal to 66/44 ≈ 1.5 moles.
How many moles of co2 form when 58 grams of butane burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
How many moles of carbon are in 0.100 moles of carbon dioxide?
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
How many moles of carbon dioxide are there in 211g of carbon dioxide?
211g of carbon dioxide are equal to 4,794 moles.
How many moles are in 85.636 grams of carbon?
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
How many moles of carbon dioxide is present in 220mg?
First, convert the mass of carbon dioxide to grams by dividing by 1000: 220 mg = 0.22 g. Next, use the molar mass of carbon dioxide (44 g/mol) to calculate the number of moles: 0.22 g / 44 g/mol = 0.005 moles of carbon dioxide.
How many grams of carbon dioxide are produced when 7.5 grams of sodium carbonate reacts with nitric acid?
First write the balance equation: Na2CO3 + 2HNO3 ==> 2NaNO3 + CO2 + H2O Next calculate moles of Na2CO3 used: 7.5 g x 1 mole/106 g = 0.071 moles Na2CO3 Then look at mole ratio of Na2CO3 to CO2 and see that it is 1 to 1 Thus, moles CO2 produced = 0.071 moles Finally, convert moles CO2 to grams of CO2: 0.071 moles x 44g/mole = 3.1 g (to 2 significant figures)
