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How many moles of co2 form when 58 grams of butane burn in oxygen?
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∙ 6y ago
The answer is 3,99 moles of carbon dioxide.
Stefanie Raynor
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How many grams of oxygen are required to burn 4.8 mol of butane?
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
How many moles of CO2 form when 58.0 g of butane C4H10 burn in oxygen?
4 moles
How many moles of co2 form when 58.0 g of butane c4h10 burn oxygen?
4 moles
How many moles of oxygen are needed to burn 7.0 mols of phosphorus?
8,75 moles of oxygen are needed.
How many moles of O2 are needed to burn 1.35mol of C8H18?
16,875 moles of oxygen are needed.
How many moles of O2 are needed to burn 10 moles of Mg?
A. A balance chemical equation of burning of ethene is C2H4 + 3O2 ____ 2CO2 + 2H2O now according to balance chemical equation 1 mole of ethene burn by using 3 moles of oxygen so to burn 10 moles of ethene 3 x 10 30 moles of oxygen will be required.
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
What fuel does the Olympic flame burn?
Butane
How many grams of o2 are needed to completely burn 96.6 grams of c3h8?
CO2 has 1 carbon atom and 2 oxygen atoms. Carbon has an atomic mass of about 12 and oxygen 16. The total for carbon dioxide is 12 + 16 + 16 = 44. The make 88gms you would need the same proportion in grams as the proportion of atomic masses. The answer is therefore 64 grams of oxygen. For each tonne of carbon burnt the oxygen from 15000 cubic metres of atmosphere is needed.
How many liters of oxygen are needed to burn 20 liters of hydrogen?
You need to state temperature and pressure of the gases I think, from this you can find the number of moles of both. The equation is 2H2 + O2 => 2H2O calculate the moles burned (for every 2 moles h2, 1 mole of O2 will burn.
How many moles of O2 are needed to burn 1.50 moles of C8H18?
Balance this combustion reaction first! 2C4H10 + 13O2 -> 8CO2 + 10H2O 0.86 moles C4H10 (13 moles O2/2 moles C4H10) = 5.6 moles of oxygen required ----------------------------------------
