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Balance this combustion reaction first!
2C4H10 + 13O2 -> 8CO2 + 10H2O
0.86 moles C4H10 (13 moles O2/2 moles C4H10)
= 5.6 moles of oxygen required
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Wiki User
∙ 12y ago
kierra jones
How many moles of O2 are needed to burn 1.40 mol of C8H18?
Wiki User
∙ 13y ago2 C6H14 + 19O2 = 12CO2 + 14H2O so 5.8/2 x 19 = 55.1 moles of O2
Wiki User
∙ 13y ago2 C6H14 + 19O2 = 12CO2 + 14H2O so 4.4/2 x 19 = 41.8 moles of O2
Wiki User
∙ 13y agoCombustion reaction balanced equation first.
2C6H6 + 15O2 -> 12CO2 + 6H2O
1.25 moles C6H6 (15 moles O2/2 moles C6H6)
= 9.38 moles O2 needed
Wiki User
∙ 6y agoC3H8 + 5O2 à 3CO2 + 4H2O
So 5 moles of oxygen are needed for each mole of propane. The answer is 12.5 moles.
Wiki User
∙ 16y ago81.25 moles of O2 or 162 moles of O atoms
Wiki User
∙ 8y agoThe answer is 3 moles oxygen.
Wiki User
∙ 7y ago18,75 moles of oxygen are needed.
Wiki User
∙ 11y ago62 mol
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How many moles of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
How many atoms of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18)(6.022 X 10^23/1 mole H) = 2.2 X 10^25 atoms of hydrogen
How many moles of O2 are needed to burn 10 moles of Mg?
A. A balance chemical equation of burning of ethene is C2H4 + 3O2 ____ 2CO2 + 2H2O now according to balance chemical equation 1 mole of ethene burn by using 3 moles of oxygen so to burn 10 moles of ethene 3 x 10 30 moles of oxygen will be required.
How many moles of C are needed to react with 0.490mole SO2?
How many moles of C are needed to react with 0.490 mole SO2?
How do you find if you have 14.5 moles of N2 how many moles of H2 are theoretically needed to produce 22.5 moles of NH3 according to the reaction N2 plus 3H2 2NH3?
N2 + 3H2 -> 2NH3 If you have moles produced you can do it this way. 22.5 moles NH3 (3 moles H2/2 moles NH3) = 33.8 moles H2 needed -----------------------------------
How many moles of O2 are needed to burn 1.35mol of C8H18?
16,875 moles of oxygen are needed.
How many moles of carbon and hydrogen are there in 5 moles of octane?
Balanced equation. 2C8H18 + 25O2 -> 16CO2 + 18H2O 5.5 moles C8H18 (25 moles O2/2 moles C8H18) = 68.75 moles O2 needed
How many moles of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18) = 36 moles of hydrogen =================
How many moles of are present in 16.0 of octane?
C8H18. I assume you mean how many moles octane in 16 grams. 16 grams C8H18 (1 mole C8H18/114.224 grams) = 0.140 moles octane
How many moles of oxygen are needed to burn 7.0 mols of phosphorus?
8,75 moles of oxygen are needed.
How many atoms of H are in 2 mol of c8h18?
2 moles C8H18 (18 moles H/1 mole C8H18)(6.022 X 10^23/1 mole H) = 2.2 X 10^25 atoms of hydrogen
How many moles of carbon dioxide are formed in the complete combustion of one mole of octane C8H18?
The answer is 8 moles CO2.
How many moles of water can be produced by burning 325g of octane in excess oxygen?
Balanced equation: 2C8H18 + 25O2 ==> 16CO2 + 18H2Omoles of octane used: 325 g x 1 mole/114g = 2.85 moles octanemoles H2O produced: 18 moles H2O/2 moles C8H18 x 2.85 moles C8H18 = 25.65 moles H2O
How many moles of O2 are needed to burn 10 moles of Mg?
A. A balance chemical equation of burning of ethene is C2H4 + 3O2 ____ 2CO2 + 2H2O now according to balance chemical equation 1 mole of ethene burn by using 3 moles of oxygen so to burn 10 moles of ethene 3 x 10 30 moles of oxygen will be required.
How many liters of oxygen are needed to burn 20 liters of hydrogen?
You need to state temperature and pressure of the gases I think, from this you can find the number of moles of both. The equation is 2H2 + O2 => 2H2O calculate the moles burned (for every 2 moles h2, 1 mole of O2 will burn.
Calculate with clear arrangements how many moles of oxygen are needed to burn 1 kg of ethane and 1 kg of ethanol, respectively?
nothing
How many grams of 02(g) are needed to completely burn 23.7 g of C38H(g)?
The balanced equation is C3H8 + 5O2 ---> 3CO2 + 4H2O moles C3H8 = 23.7 g x 1 mol/44 g = 0.539 moles moles O2 needed = 5 x 0.539 moles = 2.695 moles O2 (it takes 5 moles O2 per mole C3H8) grams O2 needed = 2.695 moles x 32 g/mole = 86.2 grams O2 needed (3 sig figs)
