C8H18. I assume you mean how many moles octane in 16 grams.
16 grams C8H18 (1 mole C8H18/114.224 grams)
= 0.140 moles octane
This amount may be different because rust is not a clearly definite compound.
To find the number of moles of argon in 160 grams, you can use the molar mass of argon, which is approximately 40 g/mol. Using the formula: [ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} ] we can calculate: [ \text{Number of moles} = \frac{160 \text{ g}}{40 \text{ g/mol}} = 4 \text{ moles} ] Thus, there are 4 moles of argon in 160 grams.
160 centimeters are 1.60 meter.
160 cm = 160/2.54 jnches = 63 inches
To determine the amount of iron oxide (Fe2O3) formed, we first need to identify the limiting reactant. The molar mass of Fe is approximately 56 g/mol and for O2, it is about 32 g/mol. Calculating the moles, 112 g of Fe gives 2 moles (112 g / 56 g/mol), and 24 g of O2 gives 0.75 moles (24 g / 32 g/mol). The balanced reaction shows that 4 moles of Fe react with 3 moles of O2; thus, O2 is the limiting reactant. According to the stoichiometry, 0.75 moles of O2 will produce 1.0 mole of Fe2O3, which corresponds to approximately 160 g (1 mole of Fe2O3 is 160 g). Therefore, 160 g of iron oxide is formed.
This amount may be different because rust is not a clearly definite compound.
To determine the number of moles in 160g of MgO, you first need to calculate the molar mass of MgO, which is 40.3 g/mol for Mg and 16.0 g/mol for O. Adding these together gives a molar mass of 56.3 g/mol for MgO. Next, divide the given mass (160g) by the molar mass of MgO to find the number of moles present. So, 160g / 56.3 g/mol = 2.84 moles of MgO.
To find the number of moles of argon in 160 grams, you can use the molar mass of argon, which is approximately 40 g/mol. Using the formula: [ \text{Number of moles} = \frac{\text{mass (g)}}{\text{molar mass (g/mol)}} ] we can calculate: [ \text{Number of moles} = \frac{160 \text{ g}}{40 \text{ g/mol}} = 4 \text{ moles} ] Thus, there are 4 moles of argon in 160 grams.
For each mole of methane hydrate, there are 5.75 moles of water associated with it. In this case, since you have 160 cm³ of methane and 1000g of water, we first convert 160 cm³ of methane to moles, which is 5.62 moles. Then we calculate the moles of water based on the ratio 1:5.75 for methane to water in methane hydrate, which gives us approximately 32.3 moles of water associated with the 5.62 moles of methane.
160 at present and these includes hotels from 1-5 star ratings
To find the number of moles in 160g of bromine molecules, we first need to determine the molar mass of bromine which is approximately 79.9 g/mol. Then, we can use the formula: moles = mass / molar mass. Therefore, moles = 160g / 79.9 g/mol ≈ 2 moles.
4 moles or 160 g NaOH is required for one litre solution.
Stock: 215 hp -Airekah This may be what both engines produce at the crank on 91 Octane fuel. At the rear wheel the automatic will give about 160 hp and the manual will give 180. A bit more on 93 octane, maybe another hp or two.
160
His weight usually runs about 160.
To find the number of moles in 160g of MgO, you first need to calculate the molar mass of MgO which is 40.3 g/mol for Mg + 16.0 g/mol for O = 56.3 g/mol for MgO. Then, divide the given mass by the molar mass to get the number of moles: 160g / 56.3 g/mol = 2.84 moles of MgO.
it is 160 ft