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160 grams MgO (1 mole MgO/40.31 grams)

= 3.97 mole magnesium oxide

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How many moles are present in 160g of MgO?

To determine the number of moles in 160g of MgO, you first need to calculate the molar mass of MgO, which is 40.3 g/mol for Mg and 16.0 g/mol for O. Adding these together gives a molar mass of 56.3 g/mol for MgO. Next, divide the given mass (160g) by the molar mass of MgO to find the number of moles present. So, 160g / 56.3 g/mol = 2.84 moles of MgO.


How many grams in 4 moles of Na OH?

40*4=160g


How many moles of Br2 are there in 160g?

1,012 mole of bromine for the diatomic molecule.


How many moles of MgO are produced from 11.2 L O2?

To determine the number of moles of MgO produced from 11.2 L of O2, you would first need to balance the chemical equation for the reaction involving MgO and O2. Then, using the ideal gas law and stoichiometry, you can calculate the moles of MgO produced.


How many mols are in 400g MgO?

The answer is 9,92 moles.


How many moles are there in 160g of bromine molecules?

To find the number of moles in 160g of bromine molecules, we first need to determine the molar mass of bromine which is approximately 79.9 g/mol. Then, we can use the formula: moles = mass / molar mass. Therefore, moles = 160g / 79.9 g/mol ≈ 2 moles.


How many moles are in 106 grams of MgO?

To determine the number of moles in 106 grams of MgO, you need to divide the given mass by the molar mass of MgO. The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg + 16 g/mol for O). Thus, 106 g / 40.3 g/mol = approximately 2.63 moles of MgO.


How many moles are in 106 g of MgO?

To find the number of moles in 106 g of MgO, you first need to calculate the molar mass of MgO. The molar mass of MgO is 40.3 g/mol for Mg and 16.0 g/mol for O, so the total molar mass is 56.3 g/mol. To find the number of moles, divide the given mass by the molar mass: 106 g ÷ 56.3 g/mol ≈ 1.88 moles of MgO.


How many moles are present in 1g of MgO?

2 Mg(OH)2 have 10 atoms.


How many oxygen atoms in 0.800 moles MgO?

In 0.800 moles of MgO, there are the same number of oxygen atoms as there are in 0.800 moles of O atoms. One mole of MgO contains one mole of oxygen atoms, which is equivalent to 6.022 x 10^23 oxygen atoms.


The number of moles of MgO produced when 0.200 mol of O2 reacts completely with magnesium is?

The balanced chemical equation for the reaction is: 2 Mg + O2 → 2 MgO. This means that for every 1 mole of O2, 2 moles of MgO are produced. Therefore, if 0.200 mol of O2 reacts completely, it will produce 0.400 mol of MgO.


How 2 moles of Magnesium oxide are formed when 4 moles of Mg reacts with O?

2Mg + O2 -----> 2MgO So two moles of magnesium oxide are formed if x moles of magnesium are allowed to react with only 1 mole of oxygen molecules. The oxygen has become the limiting ingredient.