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How many moles are in 987 grams of Ra(OH)2?
987 grams of Ra(OH)2 is equivalent to 3,78 moles.
How many moles in 987 grams of Ra(OH)2?
987 grams of Ra(OH)2 is equal to 3,78 moles.
Convert grams to moles?
To convert grams to moles, you need to know the molar mass of the substance. Divide the given mass in grams by the molar mass to find the number of moles. This calculation is done using the formula: moles = grams / molar mass.
How many grams of calcium sulfate will be formed if 130 grams of calcium hydroxide reacts with an excess of sulfuric acid?
To determine the grams of calcium sulfate formed from 130 grams of calcium hydroxide (Ca(OH)₂), we first need to calculate the moles of Ca(OH)₂. The molar mass of Ca(OH)₂ is approximately 74.09 g/mol, so 130 g corresponds to about 1.76 moles. The balanced chemical equation for the reaction with sulfuric acid (H₂SO₄) produces one mole of calcium sulfate (CaSO₄) for each mole of calcium hydroxide. Therefore, 1.76 moles of Ca(OH)₂ will yield 1.76 moles of CaSO₄, which is approximately 246.5 grams (using the molar mass of CaSO₄, about 136.14 g/mol).
What is the gram to mole converson for CaOH2?
To convert grams of calcium hydroxide (Ca(OH)₂) to moles, you need to know its molar mass. The molar mass of Ca(OH)₂ is approximately 74.09 g/mol (calcium = 40.08 g/mol, oxygen = 16.00 g/mol × 2, hydrogen = 1.01 g/mol × 2). To convert grams to moles, divide the mass of Ca(OH)₂ in grams by its molar mass: moles = grams / 74.09 g/mol.
How many moles are in 987 grams of Ra(OH)2?
987 grams of Ra(OH)2 is equivalent to 3,78 moles.
How many moles in 987 grams of Ra(OH)2?
987 grams of Ra(OH)2 is equal to 3,78 moles.
How many grams of Na OH are needed to prepare 75.0 g of Na OH?
75g
What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
What is 7.555 grams Na OH when converted to ml?
It isn't a Na OH.
How many grams of CaOH2 are needed to prepare 300.0 mL of a 0.115 M solution?
Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed
How many moles of BaOH2 are in 2400 grams of BaOH 2?
To find the number of moles in 2400 grams of Ba(OH)2, divide the given mass by the molar mass of Ba(OH)2. The molar mass of Ba(OH)2 is 171.34 g/mol. So, 2400 g / 171.34 g/mol = 14.00 mol of Ba(OH)2.
How many grams of NaOH are in 1.25 mol NaOH?
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
Convert grams to moles?
To convert grams to moles, you need to know the molar mass of the substance. Divide the given mass in grams by the molar mass to find the number of moles. This calculation is done using the formula: moles = grams / molar mass.
Which equation shows how to calculate how many grams(g) of Mg(OH)2 would be produced from 4 mol KOH. The balanced reaction is mgcl2 plus 2koh mg(oh)2 plus 2kcl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Which equation shows how to calculate how many grams (g) of Mg(OH)2 would be produced from 4 mol of KOH The balanced reaction is MGCl2 plus 2KOH Mg(OH)2 plus 2KCl?
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
How do you Convert 42 grams AlOH3 to moles AlOH3?
That is aluminum hydroxide and as a polyatomic ion hydroxide needs to be in parenthesis. Thus; Al(OH)3 This shows aluminum's 3+ oxidation state and the three matching hydroxides 1- state. 42 grams Al(OH)3 ( 1 mole Al(OH)3/78.004 grams) = 0.538 moles Al(OH)3 As significant figures require; 0.54 moles Al(OH)3
