40*4=160g
987 grams of Ra(OH)2 is equivalent to 3,78 moles.
987 grams of Ra(OH)2 is equal to 3,78 moles.
To convert grams to moles, you need to know the molar mass of the substance. Divide the given mass in grams by the molar mass to find the number of moles. This calculation is done using the formula: moles = grams / molar mass.
2 moles of Ca and 4 moles of OH
To determine the grams of calcium sulfate formed from 130 grams of calcium hydroxide (Ca(OH)₂), we first need to calculate the moles of Ca(OH)₂. The molar mass of Ca(OH)₂ is approximately 74.09 g/mol, so 130 g corresponds to about 1.76 moles. The balanced chemical equation for the reaction with sulfuric acid (H₂SO₄) produces one mole of calcium sulfate (CaSO₄) for each mole of calcium hydroxide. Therefore, 1.76 moles of Ca(OH)₂ will yield 1.76 moles of CaSO₄, which is approximately 246.5 grams (using the molar mass of CaSO₄, about 136.14 g/mol).
987 grams of Ra(OH)2 is equivalent to 3,78 moles.
987 grams of Ra(OH)2 is equal to 3,78 moles.
75g
Molarity = moles solute/Liters solution get moles NaOH 0.240 grams NaOH (1 mole NaOH/39.998 grams) = 0.0060 moles NaOH ----------------------------------as one to one OH- has this many moles also Molarity = 0.0060 moles OH-/0.225 Liters = 0.0267 M OH- ----------------------- -log(0.0267 M OH-) = 14 - 1.573 = 12.4 pH -------------
It isn't a Na OH.
Molarity = moles of solute/Liters of solution ( 300.0 ml = 0.300 liters ) ( Ca(OH)2 is correct formulation ) 0.115 M Ca(OH)2 = moles Ca(OH)2/0.300 Liters = 0.0345 moles Ca(OH)2 (74.096 grams/1 mole Ca(OH)2) = 2.56 grams of Ca(OH)2 needed
To convert grams to moles, you need to know the molar mass of the substance. Divide the given mass in grams by the molar mass to find the number of moles. This calculation is done using the formula: moles = grams / molar mass.
To find the number of moles in 2400 grams of Ba(OH)2, divide the given mass by the molar mass of Ba(OH)2. The molar mass of Ba(OH)2 is 171.34 g/mol. So, 2400 g / 171.34 g/mol = 14.00 mol of Ba(OH)2.
5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 ) = 0.0306 moles Ba(OH)2
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
Two moles KOH for one mole Mg(OH)2; so for 4 moles KOH - two moles Mg(OH)2.And two moles Mg(OH)2 is equal to 116,64 g.
The atomic weight of Na-OH is 23+16+1= 40. So to prepare the one N solution of Na-OH, you need to add 40 grams of Na-OH in one litre of water. To prepare the 4N Na-OH solution, you need to add 160 grams of Na-OH in one litre of water.