5.25 grams Ba(OH)2 (1mol Ba(OH)2/171.316 grams Ba(OH)2 )
= 0.0306 moles Ba(OH)2
To calculate the grams of NaOH, first find the molar mass of NaOH (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H) = 40.00 g/mol. 9.03 x 10^23 molecules of NaOH is equivalent to 1 mole of NaOH. Therefore, 9.03 x 10^23 molecules of NaOH is equal to 40.00 grams.
To convert grams of NaOH to moles, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). Thus, 20 grams of NaOH is equivalent to 0.5 moles (20 g / 40 g/mol).
2.2 moles of NaOH weigh 99.55 grams. This is calculated by multiplying the number of moles by the molar mass of NaOH, which is 40 grams per mole for Na (22.99 g/mol) + O (16.00 g/mol) + H (1.01 g/mol).
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
To find the number of moles, you need to divide the given mass (15 grams) by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (22.99 g/mol for Na + 16 g/mol for O + 1.01 g/mol for H). So, 15 grams / 40 g/mol = 0.375 moles of NaOH.
To determine the grams of sodium hydroxide in 0.150 mol, you need to use the molar mass of NaOH, which is 40.00 g/mol (Na = 22.99 g/mol, O = 16.00 g/mol, H = 1.01 g/mol). 0.150 mol NaOH x 40.00 g/mol = 6.00 grams of NaOH.
To calculate the grams of NaOH, first find the molar mass of NaOH (22.99 g/mol for Na + 16.00 g/mol for O + 1.01 g/mol for H) = 40.00 g/mol. 9.03 x 10^23 molecules of NaOH is equivalent to 1 mole of NaOH. Therefore, 9.03 x 10^23 molecules of NaOH is equal to 40.00 grams.
To convert grams of NaOH to moles, you need to divide the given mass by the molar mass of NaOH. The molar mass of NaOH is approximately 40 g/mol (sodium: 23 g/mol, oxygen: 16 g/mol, hydrogen: 1 g/mol). Thus, 20 grams of NaOH is equivalent to 0.5 moles (20 g / 40 g/mol).
2.2 moles of NaOH weigh 99.55 grams. This is calculated by multiplying the number of moles by the molar mass of NaOH, which is 40 grams per mole for Na (22.99 g/mol) + O (16.00 g/mol) + H (1.01 g/mol).
3.42 moles NaOH (39.998 grams/1 mole NaOH) = 137 grams NaOH
The molar mass of sodium hydroxide (NaOH) is approximately 40 g/mol. To find the mass of 2.75 moles of NaOH, you would multiply the number of moles by the molar mass: 2.75 moles x 40 g/mol = 110 grams.
To find the number of moles in 9.4 g of NaOH, you first need to calculate the molar mass of NaOH (22.99 g/mol for Na, 15.999 g/mol for O, and 1.008 g/mol for H). Add these together to get 39.997 g/mol for NaOH. Next, divide the given mass by the molar mass to get the number of moles: 9.4 g / 39.997 g/mol ≈ 0.235 moles of NaOH.
To find the number of moles, you need to divide the given mass (15 grams) by the molar mass of sodium hydroxide. The molar mass of NaOH is 40 g/mol (22.99 g/mol for Na + 16 g/mol for O + 1.01 g/mol for H). So, 15 grams / 40 g/mol = 0.375 moles of NaOH.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
To find the number of moles of NaOH in 8 g, first calculate the molar mass of NaOH (sodium hydroxide) which is approximately 40 g/mol (sodium - 23 g/mol, oxygen - 16 g/mol, hydrogen - 1 g/mol). Then, divide the given mass (8 g) by the molar mass to get the number of moles. So, 8 g / 40 g/mol = 0.2 moles of NaOH.
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
To calculate the molarity, you first need to convert the grams of NaOH to moles using the molar mass of NaOH (40 g/mol). Then, you divide the moles of NaOH by the volume of solution in liters (450 ml = 0.45 L) to get the molarity. Molarity = moles of NaOH / volume of solution in liters Moles of NaOH = 95 g / 40 g/mol = 2.375 mol Molarity = 2.375 mol / 0.45 L = 5.28 M