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If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
What is the balanced equation for sodium hydroxide and copper III chloride?
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
3M sodium hydroxide?
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 3.50 L of 0.700 M nitric acid solution?
First, calculate the number of moles of nitric acid present in 3.50 L of 0.700 M solution. Since nitric acid is a diprotic acid, the mole ratio with sodium hydroxide is 1:2. Then, use the mole ratio to determine the number of moles of sodium hydroxide needed to neutralize the nitric acid. Finally, convert the moles of sodium hydroxide to grams using its molar mass.
What is the mass in grams of 25 mol of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams/mol. To find the mass of 25 moles of NaOH, you would multiply the number of moles by the molar mass: 25 mol * 40 g/mol = 1000 grams. So, the mass of 25 moles of sodium hydroxide is 1000 grams.
If you have 60 grams of sodium hydroxide NaOH (FW 40 gramsmole) how many moles of sodium hydroxide would you have?
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
How many moles are in 8 grams of sodium hydroxide?
0.2 mol
What is 83 grams of sodium hydroxide in moles?
For this you need the atomic (molecular) mass of NaOH. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaOH= 40.083.0 grams NaOH / (40.0 grams)= 2.08 moles NaOH
How many grams of sodium hydroxide are there in 0.150 mol?
To find the grams of sodium hydroxide in 0.150 mol, first calculate the molar mass of sodium hydroxide, which is approximately 40 g/mol. Then, multiply the molar mass by the number of moles: 40 g/mol x 0.150 mol = 6 grams of sodium hydroxide.
How many grams of sodium hydroxide are present in 675 mL of a 0.500M solution?
To calculate the grams of sodium hydroxide present in the solution, first calculate the number of moles using the formula: moles = Molarity (M) x Volume (L). Then, use the molar mass of sodium hydroxide (NaOH) to convert moles to grams. The molar mass of NaOH is 40 g/mol. Thus, in this case, you have 0.3375 moles of NaOH and if you convert this to grams, it would be 13.5 grams.
How many MOLES of sodium nitrate are present in 2.85 grams of this compound?
To find the number of moles, first calculate the molar mass of sodium nitrate (NaNO3), which is 85 grams/mol. Then, divide the given mass (2.85 grams) by the molar mass to obtain the number of moles present, which is approximately 0.0335 moles.
How many moles of sodium hydroxide are in 40 grams of sodium hydroxide?
To find the number of moles in 40 grams of sodium hydroxide, you first need to calculate the molar mass of NaOH. The molar mass of NaOH is about 40 g/mol. Then, you divide the given mass by the molar mass to get the number of moles. So, 40 grams divided by 40 g/mol is equal to 1 mole of NaOH.
How do you the stoichiometry problem 2 NaOH plus H2SO4---2 H2O plus Na2SO4how many grams of sodium sulfate will be formed if you start with 200 grams of sodium hydroxide and you have an excessofsulfur?
To solve this stoichiometry problem, first calculate the number of moles of sodium hydroxide (NaOH) present in 200 grams. Then, using the balanced equation, determine the moles of sodium sulfate (Na2SO4) that will be formed. Finally, convert the moles of Na2SO4 to grams using the molar mass of sodium sulfate.
How many grams are in a 6.94 mole sample of sodium hydroxide?
The molar mass of sodium hydroxide (NaOH) is approximately 40 grams per mole. Therefore, a 6.94 mole sample of sodium hydroxide would contain approximately 278 grams (6.94 moles x 40 grams/mole).
What is the balanced equation for sodium hydroxide and copper III chloride?
The balanced chemical equation for the reaction between sodium hydroxide and copper(III) chloride is: 2NaOH + 3CuCl3 → 3Cu(OH)3 + 6NaCl This equation shows that two moles of sodium hydroxide react with three moles of copper(III) chloride to produce three moles of copper(III) hydroxide and six moles of sodium chloride.
3M sodium hydroxide?
C2H4O2 + NaOH = H2O + C2H3O2Na Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm water (18 gm) + sodium acetate (82 gm) = 100 gm Ratio reactants to products = 1:1 Molarity = moles / L, 3M = 3 moles / 1 L Acetic acid = 60 gm / total reactant 100gm = 1.8 moles Multiply by 3 = 1.8 moles or 180 grams Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams. 180 grams acetic acid + 120 grams sodium hydroxide = 300 grams. 300 grams divided by 1 liter = 3M So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.
