3M sodium hydroxide

Answer 1

C2H4O2 + NaOH = H2O + C2H3O2Na

Acetic acid (60 gm) + sodium hydroxide ( 40 gm) = 100 gm

water (18 gm) + sodium acetate (82 gm) = 100 gm

Ratio reactants to products = 1:1

Molarity = moles / L, 3M = 3 moles / 1 L

Acetic acid = 60 gm / total reactant 100gm = 1.8 moles

Multiply by 3 = 1.8 moles or 180 grams

Sodium Hydroxide = 40 gm / total reactant 100 mg = 1.2 moles or 120 grams.

180 grams acetic acid + 120 grams sodium hydroxide = 300 grams.

300 grams divided by 1 liter = 3M

So in order to make 3 M sodium acetate combine solution, add 180 grams acetic acid and 120 grams sodium hydroxide with 1 liter of water.