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What volume(L) of 3M KOH solution can be perpared by diluting 0.5 L of %M KOH solution?

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What is the molarity of a KOH solution if 24.6 mL neutralizes 44.0 mL of a 0.211 M HCl?

To find the molarity of the KOH solution, we first need to determine the number of moles of HCl used in the reaction (n(HCl) = Molarity x Volume). Then, since KOH and HCl react in a 1:1 ratio, the number of moles of KOH will be the same. Finally, calculate the molarity of KOH using the moles of KOH and the volume of KOH solution used.


How many moles of KOH are contained in 750. mL of 5.00 M KOH solution?

To determine the number of moles of KOH in the solution, you can use the formula: moles = molarity x volume (L) First, convert the volume from mL to liters by dividing 750 mL by 1000. Then, multiply the molarity (5.00 M) by the volume in liters to find the number of moles of KOH in the solution.


What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH?

To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.


What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?

The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.


How do you prepare 30 percent of methanolic KOH solution?

To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.

Related Questions

What is the molarity of a KOH solution if 24.6 mL neutralizes 44.0 mL of a 0.211 M HCl?

To find the molarity of the KOH solution, we first need to determine the number of moles of HCl used in the reaction (n(HCl) = Molarity x Volume). Then, since KOH and HCl react in a 1:1 ratio, the number of moles of KOH will be the same. Finally, calculate the molarity of KOH using the moles of KOH and the volume of KOH solution used.


How many moles of KOH are contained in 750. mL of 5.00 M KOH solution?

To determine the number of moles of KOH in the solution, you can use the formula: moles = molarity x volume (L) First, convert the volume from mL to liters by dividing 750 mL by 1000. Then, multiply the molarity (5.00 M) by the volume in liters to find the number of moles of KOH in the solution.


What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH?

To find the concentration of the final solution, you need to calculate the total moles of KOH before and after dilution. The initial moles of KOH can be found using the initial volume and concentration. Then, calculate the final volume of the solution after dilution and use it to determine the final concentration of KOH.


What is the concentration of an HBr solution if 12.0 mL of the solution is neutralized by 15.0 mL of a 0.25 M KOH solution?

The reaction between HBr and KOH is a 1:1 ratio. This means that the moles of HBr present in the solution will be equal to the moles of KOH used in the neutralization reaction. Using this information and the volume and concentration of KOH used, you can calculate the concentration of the HBr solution.


How do you prepare 30 percent of methanolic KOH solution?

To prepare a 30% methanolic KOH solution, you would mix 30g of KOH with enough methanol to make a total solution volume of 100mL. This would result in a solution where 30% of the total weight comes from KOH. Be cautious when handling KOH as it is a caustic substance and should be handled with appropriate precautions.


An acid solution is 0.120 m in hcl and 210 m in h2so4 what volume of a 150 m koh solution would have to be added to 500.0 ml of the acidic solution to neutralize completely all of the acid?

To find the volume of KOH solution needed to neutralize the acidic solution, you'll need to determine the moles of acid present and use the stoichiometry of the neutralization reaction. Calculate the moles of HCl and H2SO4 separately, and then find the limiting reactant. Finally, use the balanced chemical equation to determine the moles of KOH needed, which can then be converted to volume using the concentration of the KOH solution.


If 25.0 ml of 1.48m h2so4 can be neutralized with 27.29 ml of koh what is the molarity of the koh?

25 milliliters of the solution has . 037 moles of H2SO4. The neutralization reaction is H2SO4 + 2 KOH yields 2 H2O + K2SO4. So, . 074 moles of KOH are required. This equals 2. 71 mL of solution.


What will be the molarity for a solution prepared by dissolving 50 grams of KOH in 700ml of water?

Molarity= Number of moles of solute/Liters of solution 50 grams KOH 700 ML to .7 Liters of h2o Molar Mass of KOH= 56 50 divided by 56 = .89 moles Molarity= .89 mol/.7 L = 1.27 MOLARITY


A 25 ml sample of 723 m hclo4 is titrated with a 273 m koh solution the h3o concentration after 66.2 ml of koh is?

The balanced chemical equation for the reaction between HClO4 and KOH is HClO4 + KOH → KClO4 + H2O. By using the stoichiometry of the reaction, you can calculate the moles of HClO4 reacted with KOH. Then, use the remaining volume of KOH solution added to calculate the final H3O+ concentration in the solution.


A 10.0 ml of 0.121 m h2so4 is neutralized by 17.1 ml of koh solution the molarity of the koh soultion is?

First, calculate the number of moles of H2SO4: Moles H2SO4 = volume (L) * concentration (mol/L) Next, use the balanced equation to determine the mole ratio between H2SO4 and KOH. The balanced equation is H2SO4 + 2KOH -> K2SO4 + 2H2O. Then, calculate the molarity of KOH: Molarity KOH = moles of KOH / volume of KOH solution (L)


How do you prepare 1N alcoholic koh solution?

To prepare a 1N alcoholic KOH solution, you will need to dissolve the appropriate amount of potassium hydroxide (KOH) pellets in a specific volume of anhydrous ethanol. First, calculate the molecular weight of KOH (39.10 g/mol) and then measure out the required weight to make a 1N solution. Once weighed, slowly add the KOH pellets into the anhydrous ethanol while stirring until fully dissolved. Check the final volume to ensure it reaches 1N concentration. Remember to handle KOH with care as it is caustic and generate heat when dissolving in ethanol.


Why freshly prepared 'KOH' solution is taken in a watch-glass and kept in the bell jar during the experiment to show that carbon-dioxide is essential for photosynthesis?

The freshly prepared KOH solution is used in the experiment to absorb carbon dioxide present in the air inside the bell jar. By keeping the KOH solution in a watch-glass, any change in the color of the solution due to the absorption of carbon dioxide can be easily observed. This helps demonstrate that carbon dioxide is essential for photosynthesis by showing that the removal of carbon dioxide inhibits the process.