Molarity = moles of solute/volume of solution
0.500 M KOH = moles KOH/125 ml
62.5 millimoles, or to answer the question precisely,
0.0625 moles KOH
M=n/v
1.5M KOH = 0.132/v
v=0.132/1.5=0.88
0.88*1000ML=88ML
Molarity=Moles of solute/Liters of solution
1.350 g KOH = 0.02406 mol KOH
0.02406 mol/0.2500 L =0.09624 M of KOH
You can prepare 250 mL of a 2,5 % solution.
This solution - 750 mL of 5 M KOH - contain 3,75 moles of KOH.
35,0 mL of a 5,50 M KOH solution contain 10,8 g KOH.
This amount is 3,75 moles.
3.75 mol
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
Molarity is per litre. So whatever you do to convert the volume back to per litre you have to do to the moles. 2.5/500, x1000 is 5 molar.
500 grams of radium is equal to 2,21 moles.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
3.01 x 10 23 molecules
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
The answer is 1,5 moles.
The answer is 0,1 mol.
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
Molarity is per litre. So whatever you do to convert the volume back to per litre you have to do to the moles. 2.5/500, x1000 is 5 molar.
500 grams of radium is equal to 2,21 moles.
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
3.01 x 10 23 molecules
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M