0
What is the total number of moles in 500 ml of a 3.0 M solution of Kl solution?
Wiki User
∙ 9y ago
The answer is 1,5 moles.
Wiki User
∙ 8y ago
Add your answer:
Earn +20 pts
How many moles of KI are present in 500 ml of a 0.2M solution?
The answer is 0,1 mol.
What is the molarity of the resulting solution obtained by mixing 2.5liter of 0.5M urea solution and 500 ml of 2M urea solution?
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
What is the molarity of a solution that is made using 1.2 moles of a substance in 500mL?
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
How many moles are in 500 liters?
You have to say which chemical you have 500 liters of. Moles are not a unit of volume, they refer to a specific number (Avogadro's number) of molecules, and different substances have different molecular sizes.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
Molarity = moles of solute/volume of solution 0.324 M H2SO4 = moles H2SO4/500 ml 162 millimoles, or, more precisely to the question 0.162 moles H2SO4
How many moles of sodium chloride are needed to prepare 500 mL of a 0.250 M solution?
500ml = 500cm3 = 0.5dm3 0.250M = 0.250mol/dm3 number of moles = molarity x volume number of moles = 0.250mol/dm3 x 0.5dm3 = 0.125mol 0.125mol of NaCl is needed to prepare the required solution.
What is the molarity of a solution that has 2.5 moles of solute dissolved in 500 mililiter of solution?
Molarity is per litre. So whatever you do to convert the volume back to per litre you have to do to the moles. 2.5/500, x1000 is 5 molar.
What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?
Need moles aluminum oxide first. 51 grams Al2O3 (1 mole Al2O3/101.96 grams) = 0.5002 moles Al2O3 ======================Now, Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters ) Molarity =0.5002 moles Al2O3/0.500 Liters = 1.0 M Al2O3 solution ----------------------------
How many moles of KI are present in 500 ml of a 0.2M solution?
The answer is 0,1 mol.
What is the molarity of the resulting solution obtained by mixing 2.5liter of 0.5M urea solution and 500 ml of 2M urea solution?
The 0.5M and 2M refer to moles per liter (of solution). Volume of final solution is 2.5 L + 500 mL = 2.5 L + 0.5 L = 3.0 L. So find out how many moles the final solution has and divide by 3.0L.First solution (0.5 moles/liter)*(2.5 liter) = 1.25 moles2nd solution (2 moles/liter)*(0.5 liter) = 1 moleMolarity: (1.25 mole + 1 mole)/(3.0 liter) = 0.75 moles/liter = 0.75 M
How many moles of KMnO4 are present in 75.0 mL of a 0.0950 M solution?
Molarity = moles of solute/Liters of solution ( 75.0 ml = 0.075 Liters ) Algebraically manipulate, moles of solute = Liters of solution * Molarity Moles KMnO4 = (0.075 Liters)(0.0950 M) = 7.13 X 10 -3 moles KMnO4 ------------------------------------
How many moles of KCl are needed to prepare 1.00 L of a 1.0M KCl solution?
M= moles in solution/liters so plug in what you know 3.0M of KCl solution = moles in solution/ 2.0L multiply both sides by 2.0L moles solute = 1.5 moles KCl so you need 1.5 moles KCl to prepare the solution
What is the molarity of a solution that is made using 1.2 moles of a substance in 500mL?
Molarity (M) is defined as moles of solute/liters of solution. Assuming the final volume is 500 ml (0.5 liters), then M = 1.2 moles/0.5 liters = 2.4 M
How is 500 ml of 0.25-M solution prepared?
The question is a little ambiguous so I'll answer it the best way I can. Concentration (M) is the number of moles of a substance divided by the volume that it is dissolved in. This leads to the expression c = n/V Where n is the number of moles, V is the volume in litres and c is the concentration. In answer to the question, 500 ml of 0.25M solution can be prepared as follows: c = n/V Therefor: 0.25 = n/0.5L n = 0.125 mol 500ml of an 0.25M solution can be prepared by dissolving 0.125 mol of the substance in 500ml (providing it dissolves).
How can i make a 10 percent glucose solution from 50 percent glucose solution?
Let's say the total solution is 100 liters. 50 of the liters is glucose and 50 is water. We want to make the 50 glucose equal to 10% of the total solution. For that to happen, we need to make the total solution 500 liters (50 of the 500 would be a 10% solution). So we add 400 liters of water to the original 100 liter (50/50) solution. Take the total number of units and multiply by 4. Add that much in water.
How many moles in 500 grams of radium?
500 grams of radium is equal to 2,21 moles.
