What is the molarity of a solution in which 51 grams of aluminum oxide Al2O3 is dissolved in 500 mL of solution?

Answer 1

Need moles aluminum oxide first.

51 grams Al2O3 (1 mole Al2O3/101.96 grams)

= 0.5002 moles Al2O3

======================Now,

Molarity = moles of solute/Liters of solution (500 ml = 0.500 Liters )

Molarity =0.5002 moles Al2O3/0.500 Liters

= 1.0 M Al2O3 solution

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Answer 2

To find the molarity, you first need to calculate the number of moles of Al2O3. The molar mass of Al2O3 is 101.96 g/mol. Since you have 51 grams, that would be 0.5 moles. Next, convert the volume from mL to liters (500 mL = 0.5 L) and then divide the moles by the volume to get the molarity, which is 1.0 M.