0
The question is a little ambiguous so I'll answer it the best way I can. Concentration (M) is the number of moles of a substance divided by the volume that it is dissolved in. This leads to the expression c = n/V Where n is the number of moles, V is the volume in litres and c is the concentration. In answer to the question, 500 ml of 0.25M solution can be prepared as follows: c = n/V Therefor: 0.25 = n/0.5L n = 0.125 mol 500ml of an 0.25M solution can be prepared by dissolving 0.125 mol of the substance in 500ml (providing it dissolves).
What else can I help you with?
What is the pH of a solution when you calculate the pH of a solution that contains 3.0 g of HI in 500 ml of water?
The pH of a solution containing 3.0 g of HI in 500 ml of water is approximately 1.7.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
To find the number of moles of sulfuric acid in the solution, multiply the volume of the solution (in liters) by the molarity. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, multiply 0.5 L by 0.324 mol/L to get 0.162 moles of sulfuric acid in 500 mL of the 0.324 M solution.
A student carefully diluted 25.0 ml 0.6 M NaOH solution in 475 ml of distilled water What is the molarity of the diluted solution of base?
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
What is the molarity of a solution prepared by combining 125 mL of 0.251 molar HCl with 250 mL of pure water?
The final volume of the solution is 375 mL (125 mL HCl + 250 mL water). As the water does not contribute to the molarity of the solution, the moles of HCl remain the same. Thus, the molarity of the final solution is 0.251 mol / (0.375 L) = 0.670 M.
How would you prepare 500 mL of a 1M solution of acetic acid -HC2H3O2- from a stock solution of 6M of acetic acid?
You would need to dilute the 6M acetic acid solution by adding the appropriate volume of water. To prepare 500 mL of 1M solution, you would need to take (1/6)th of the volume of the 6M solution, which is (1/6) x 500 mL = 83.33 mL of the 6M solution. Dilute this with water to reach a final volume of 500 mL.
How many mL of a 20 percent solution are needed to prepare 500 mL of a 5 percent solution?
125 ml 500(ml) * 0.05 = 25 25 / 0.20 = 125
How much water would I add to a 50percent solution of H2O2 to make 500 ml of 3percent H2O2?
To make a 500 ml solution of 3% H2O2 from a 50% solution, you would need to dilute the 50% solution with water. You would add 325 ml of water to 175 ml of the 50% H2O2 solution to achieve a final volume of 500 ml with a concentration of 3% H2O2.
How many grams of medication will 500 ml of a 10 percent solution contain?
To calculate the mass of medication in the solution, multiply the volume of the solution (500 ml) by the concentration of the medication (10%). Convert the percentage to a decimal by dividing by 100 (10% = 0.10). So, 500 ml x 0.10 = 50 grams of medication in 500 ml of a 10% solution.
What is the pH of a solution when you calculate the pH of a solution that contains 3.0 g of HI in 500 ml of water?
The pH of a solution containing 3.0 g of HI in 500 ml of water is approximately 1.7.
How many milliliter of a 20 percent and a 65 percent solutions should you mix together to make 500 milliliter of a 45 percent solution?
Let x be the amount of the 20% solution and y be the amount of the 65% solution. The total volume equation is: x + y = 500. The total amount of the solute equation is: 0.20x + 0.65y = 0.45(500). Solve these two equations to find the amounts of each solution needed.
What is the morality of a solution that has 120 grams of NaOH in 500 ML of solution?
6 molar
Calculate the concentration of a 500 ml solution of sucrose and water containing 125 mg of sucrose Show your calculations?
To calculate the concentration of the sucrose solution, you would divide the amount of sucrose (125 mg) by the total volume of the solution (500 ml) and then convert the units as needed: Concentration of sucrose solution = 125 mg / 500 ml = 0.25 mg/ml = 0.25 g/L
If you have an order for 20 percent dextrose 500 ml you have 1000 ml bag of dextrose 70 percent how much of the dextrose 70 percent do you need to use to make dextrose 20 percent 500 ml?
To make a 20% dextrose solution, you need to dilute the 70% dextrose solution with water. You need to use 178.57 ml of the 70% dextrose and 321.43 ml of water to make 500 ml of 20% dextrose solution.
How many moles of sulfuric acid are in 500 mL of 0.324 M sulfuric acid solution?
To find the number of moles of sulfuric acid in the solution, multiply the volume of the solution (in liters) by the molarity. First, convert 500 mL to liters by dividing by 1000 (500 mL = 0.5 L). Then, multiply 0.5 L by 0.324 mol/L to get 0.162 moles of sulfuric acid in 500 mL of the 0.324 M solution.
A student carefully diluted 25.0 ml 0.6 M NaOH solution in 475 ml of distilled water What is the molarity of the diluted solution of base?
Assuming that the 25.0 ml are added to the 475 ml of water, not diluted to that volume:Moles of NaOH in the original 25 ml = 25/1000 x 0.6 = 0.015 moles Final volume = 25 + 475 ml = 500 ml. We have 0.015 moles in 500 ml, so 0.03 moles in a litre, Molarity = 0.03.
What is the total number of moles in 500 ml of a 3.0 M solution of Kl solution?
The answer is 1,5 moles.
How many moles of KI are present in 500 ml of a 0.2M solution?
The answer is 0,1 mol.
