The pH of a solution containing 3.0 g of HI in 500 ml of water is approximately 1.7.
Glucose
To calculate the molarity of the solution, first convert the mass of HCl to moles using its molar mass. Then, divide the number of moles by the volume of the solution in liters (500 cm3 = 0.5 L) to get the molarity.
Take 100 grams of 5% solution and do one of the following:Mix 95 g of it with 5 grams of sugar to end up with 100 g of 10% solution, or, when you are short of sugar:Evaporate 50 grams of water from 100 g of the 5% solution to end up with 50 g of 10% solution.
To prepare 500 mL of a 0.5 M solution of acetic acid, you would need to take 100 mL of the 2.5 M stock solution and dilute it to 500 mL. This is because the molarity equation (M1V1 = M2V2) can be used to calculate the volume of stock solution needed for dilution.
To prepare a 2N solution of Na2CO3 in 500 mL, you would need to dissolve 42.97 grams of Na2CO3. This is calculated by first converting N to molarity (2N = 2 moles/L), then using the molar mass of Na2CO3 (105.99 g/mol) to calculate the required mass.
To calculate the concentration of the sucrose solution, you would divide the amount of sucrose (125 mg) by the total volume of the solution (500 ml) and then convert the units as needed: Concentration of sucrose solution = 125 mg / 500 ml = 0.25 mg/ml = 0.25 g/L
To make a 500 ml solution of 3% H2O2 from a 50% solution, you would need to dilute the 50% solution with water. You would add 325 ml of water to 175 ml of the 50% H2O2 solution to achieve a final volume of 500 ml with a concentration of 3% H2O2.
To calculate the mass of medication in the solution, multiply the volume of the solution (500 ml) by the concentration of the medication (10%). Convert the percentage to a decimal by dividing by 100 (10% = 0.10). So, 500 ml x 0.10 = 50 grams of medication in 500 ml of a 10% solution.
A water solution of this medicine is obtained.
To dilute 1000 ppm to 500 ppm, you need to add an equal amount of the solution without any concentration. For example, if you have 1 mL of the 1000 ppm solution, you would need to add 1 mL of water to make it 500 ppm.
To dilute 500 gallons of a 31% solution to a 15% solution you would add 533.33 gallons of the dilutant. For example, if you have 500 gallons of a 31% saline solution you would add 533.33 gallons of water to create 1033.33 gallons of a 15% saline solution.
To find the freezing point of the solution, we first calculate the molality (m) of the LiBr solution. Since 0.5 mol of LiBr is dissolved in 0.5 kg of water (500 mL of water), the molality is 1.0 m. Using the formula for freezing point depression, ΔTf = Kf * m, where Kf = 1.86 °C/m, we get ΔTf = 1.86 °C/m * 1.0 m = 1.86 °C. Thus, the freezing point of the solution is 0 °C - 1.86 °C = -1.86 °C.
Glucose
To calculate the molarity of the solution, first convert the mass of HCl to moles using its molar mass. Then, divide the number of moles by the volume of the solution in liters (500 cm3 = 0.5 L) to get the molarity.
.48 = [OH-]
Take 100 grams of 5% solution and do one of the following:Mix 95 g of it with 5 grams of sugar to end up with 100 g of 10% solution, or, when you are short of sugar:Evaporate 50 grams of water from 100 g of the 5% solution to end up with 50 g of 10% solution.
A standard plastic water bottle typically contains around 16.9 ounces or 500 milliliters of water.