Need total molar mass sodium hydroxide which you can easily get from your Periodic Table.
2.2 moles NaOH (39.998 grams/1 mole NaOH)
= 88 grams in mass
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To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
To calculate the grams of NaOH needed, you first need to find the moles of NaOH required: 205 M concentration means 205 moles/L. So, for 250 mL (0.25 L), you multiply 0.25 L by 205 moles/L to get 51.25 moles. Finally, using the molar mass of NaOH (40 g/mol), you can convert moles to grams by multiplying 51.25 moles by 40 g/mol to find you need 2050 grams of NaOH.
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
208g NaOH
To calculate the grams of NaOH in the solution, you first need to find the moles of NaOH present in 400.0 ml of the solution. The moles of NaOH can be calculated using the formula: moles = molarity x volume (in liters). Once you have the moles of NaOH, you can then calculate the grams using the formula: grams = moles x molecular weight.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
To calculate the grams of NaOH in the solution, first determine the moles of NaOH using the molarity and volume. Then, convert moles to grams using the molar mass of NaOH. The molar mass of NaOH is 40 g/mol.
60 g NaOH x 1 mole NaOH/40 g NaOH = 1.5 moles NaOH
To calculate the grams of NaOH needed, you first need to find the moles of NaOH required: 205 M concentration means 205 moles/L. So, for 250 mL (0.25 L), you multiply 0.25 L by 205 moles/L to get 51.25 moles. Finally, using the molar mass of NaOH (40 g/mol), you can convert moles to grams by multiplying 51.25 moles by 40 g/mol to find you need 2050 grams of NaOH.
First, you must find the amount of moles of NaOH, using the concentration and volume given. By lowercase m, I'm assuming you mean molality, or molals of solution, which is the equation:molality (m) = (moles of solute) / (total volume of solution (in liters))To solve for moles of NaOH, your solute, rearrange the equation by multiplying volume on both sides to get:moles solute = (molality)(total volume of solution)Next, just plug in the information you know, which is 500 mL for the total volume and 125 m for the molality.***Volume for concentration problems must be converted to liters, so remember that 1 L = 1000 mLmoles NaOH = (125 m)(0.500 L) = 62.5 molesFinally, convert this to grams by finding the molar mass of NaOH using the periodic table:22.99 + 16.00 + 1.008 = 39.998 g/mol62.5 moles (39.998 g) / (1 mol) =249.875 grams NaOH
Molarity = moles of solute/Liters of solution. ( 350 ml = 0.350 Liters ) 5.7 M NaOH = moles NaOH/0.350 Liters = 1.995 moles NaOH (39.998 grams/1 mole NaOH) = 78 grams NaOH needed ------------------------------------
To calculate the grams of solute, you need to first find the molar mass of NaOH (40 g/mol). Then, use the formula grams = moles x molar mass. The moles of NaOH in 1.8 L of a 3.5 M solution is 6.3 moles. Therefore, the grams of NaOH in 1.8 L of a 3.5 M solution is 252 grams.
Write out the equation, and remember to balance each side.Na2CO3 + Ca(OH)2 --> 2NaOH + CaCO3Molecular WeightsNa2CO3: 106 grams/moleNaOH: 40 grams/moleAlways convert your reagents into moles.(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) = 1.132 molesAccording to the balanced equation, 1 molecule of Na2CO3 generates 2 molecules of NaOH.(1.132 moles Na2CO3) x (2 moles NaOH/1 mole Na2CO3) = 2.264 moles NaOHNow determine the number of grams from 2.264 moles of NaOH.(2.264 moles NaOH) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH formed.To prevent rounding off too many times, carry out the dimensional analysis in one step:(120g Na2CO3) x (1 mole Na2CO3/106 grams Na2CO3) x(2 moles NaOH/1 mole Na2CO3) x (40 grams/ 1 mole NaOH) = 90.57 grams NaOH
Approximately 4.50 grams of NaOH are required to prepare 200 mL of a 0.450 M solution. This can be calculated using the formula: moles = Molarity x Volume (in L), and then converting moles to grams using the molar mass of NaOH.
A 0.205 M solution will have 0.205 moles per liter. 250 milliliters is 1/4 of a liter, so in that sample, there will be 0.05125 moles. NaOH has a molar mass of 39.9971 grams per mole, so 2.05 grams added to 250 mL of water will make the desired solution.