Molarity = moles solute/Liters solution
get moles NaOH
0.240 grams NaOH (1 mole NaOH/39.998 grams)
= 0.0060 moles NaOH
----------------------------------as one to one OH- has this many moles also
Molarity = 0.0060 moles OH-/0.225 Liters
= 0.0267 M OH-
-----------------------
-log(0.0267 M OH-)
= 14 - 1.573
= 12.4 pH
-------------
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
This sodium hydroxide solution has a molarity of 0,25.
7
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
Need moles sodium hydroxide first.80 grams NaOH (1 mole NaOH/39.998 grams) = 2.000 moles NaOHMolarity = moles of solute/Liters of solutionMolality = 2.000 moles NaOH/1 liter= 2 M NaOH solution===============
One liter of a one molar solution of NaOH in water contains 40g of NaOH. The quantity must be known.
The answer is 0,625 moles.
NaOH in pure state does not contain H+ ions but in solution state it does contain
This sodium hydroxide solution has a molarity of 0,25.
This solution contain 26,3 g NaOH.
7
Determine the number of moles 15.5 g NaOH 15.5 g NaOH x (1 mole NaOH/39.9971 grams NaOH) = 0.388 moles NaOH Molarity = moles NaOH/L solution 0.540 M = 0.388 moles NaOH/L soln L soln = 0.718 L --> A
Need moles sodium hydroxide first.80 grams NaOH (1 mole NaOH/39.998 grams) = 2.000 moles NaOHMolarity = moles of solute/Liters of solutionMolality = 2.000 moles NaOH/1 liter= 2 M NaOH solution===============
It is possible only if you evaporate the water.
The concentration of this solution (in NaOH) is 40 g/L.
standardization of NaoH
40 grams, this is the 1M NaOH standard laboratory solution.