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Molarity = moles solute/Liters solution

get moles NaOH

0.240 grams NaOH (1 mole NaOH/39.998 grams)

= 0.0060 moles NaOH

----------------------------------as one to one OH- has this many moles also

Molarity = 0.0060 moles OH-/0.225 Liters

= 0.0267 M OH-

-----------------------

-log(0.0267 M OH-)

= 14 - 1.573

= 12.4 pH

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Q: What is the OH- in a solution that contains 0.240 g NaOH in 0.225 L of solution?
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