2 moles of Ca and 4 moles of OH
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
That would be 2 moles of OH- (hydroxide) ions because there are 2 of them associated with each 1 of the group II metal.
Two moles is equivalent to 12,044281714.10e23 molecules, atoms or ions.
20.4
B4O7^2- + 7H2O = 4H3BO3 + 2OH- B4O7^2- : 2OH- = 1:2 Therefore there are twice the number of moles of Hydroxide ions produced as there are Borate ions
The mass of 7,346 moles of Ca(OH)2 is 544,3 g.
When Na2CO3 dissociates, it produces 3 moles of ions: 2 moles of Na+ ions and 1 mole of CO3^2- ions. So, if you have 0.5 moles of Na2CO3, you would produce 1.5 moles of ions in total.
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
There are 6 moles of nitrate ions in 2 moles of magnesium nitrate. This is because there are 3 nitrate ions (NO3-) in each formula unit of magnesium nitrate (Mg(NO3)2). So, 2 moles of Mg(NO3)2 would contain 6 moles of nitrate ions.
Na2CO32 * 2 = 4 moles sodium.===========================
There are 2 moles of KCl in the sample, so there are 2 moles of chloride ions as well. Since each molecule of KCl contains 1 chloride ion, there are 2 moles of chloride ions in total.
There are 5.2 moles of ions in 2.6 moles of K2SO4. This is because each formula unit of K2SO4 dissociates into three ions: 2K+ ions and 1 SO4^2- ion. Thus, for every mole of K2SO4, you have 3 moles of ions.
Since the charge of Mg^2+ ion is 2+ and Cl^- ion has a charge of 1-, each Mg^2+ ion will combine with 2 Cl^- ions to form MgCl2. Therefore, for 0.25 moles of Mg^2+ ions, you will need 0.50 moles of Cl^- ions for complete combination.
There are 1 mole of sodium ions in 1 mole of NaCl, as there is one sodium ion for each chlorine ion in the compound. Therefore, in 2 moles of NaCl, there are 2 moles of sodium ions, which is equal to 2 x 6.022 x 10^23 sodium ions.
c- 6. When sodium sulfate dissolves in water, it dissociates into three ions: two sodium ions (Na+) and one sulfate ion (SO4^(2-)). Therefore, 2 moles of sodium sulfate will produce a total of 6 moles of ions in solution.
There are 4.50 moles of NH4 2CO3 in 4.50 mol NH4 2CO3. Since each formula unit of NH4 2CO3 contains 2 moles of ammonium ions (NH4+), there would be 2 * 4.50 = 9.00 moles of ammonium ions in 4.50 mol NH4 2CO3.
In 1.5 moles of CaCl2, you would have 3 moles of ions or atoms of calcium and 3 moles of ions of chloride. Since CaCl2 dissociates into 1 calcium ion (Ca2+) and 2 chloride ions (2Cl-), this means you would have 3 moles of calcium ions and 6 moles of chloride ions in total.