Two moles is equivalent to 12,044281714.10e23 molecules, atoms or ions.
2 moles of Ca and 4 moles of OH
To determine how much calcium oxide (CaO) is produced, we first need to consider the balanced chemical reaction: 2 Ca + O₂ → 2 CaO. From the equation, 2 moles of calcium react with 1 mole of oxygen to produce 2 moles of calcium oxide. With 10.0 moles of calcium, it can react with 5.0 moles of oxygen, but only 3.9 moles of oxygen are available. Therefore, the limiting reactant is oxygen, producing 3.9 moles of CaO.
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
true
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
2 moles of Ca and 4 moles of OH
To determine how much calcium oxide (CaO) is produced, we first need to consider the balanced chemical reaction: 2 Ca + O₂ → 2 CaO. From the equation, 2 moles of calcium react with 1 mole of oxygen to produce 2 moles of calcium oxide. With 10.0 moles of calcium, it can react with 5.0 moles of oxygen, but only 3.9 moles of oxygen are available. Therefore, the limiting reactant is oxygen, producing 3.9 moles of CaO.
If 2 moles of Na2CrO4 react completely, they will form the same number of moles of NaCl. This is because the mole ratio between Na2CrO4 and NaCl is 1:2. Therefore, 2 moles of Na2CrO4 will form 2 moles of NaCl.
2.60 moles There are 2 moles of K in K2SO4. the total moles times two (1.3 x 2) is 2.60 moles.
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.
true
2 moles of benzene gives 12 moles of hydrogen atoms since benzene is C6H6
B4O7^2- + 7H2O = 4H3BO3 + 2OH- B4O7^2- : 2OH- = 1:2 Therefore there are twice the number of moles of Hydroxide ions produced as there are Borate ions
yes moles do drin water but not much
In the reaction between MgCl2 and KOH to form Mg(OH)2, the limiting reactant determines the amount of product formed. The balanced equation shows that 1 mole of MgCl2 reacts with 2 moles of KOH. With 3 moles of MgCl2, 6 moles of KOH are required for complete reaction, but since only 4 moles of KOH are available, KOH is the limiting reactant. Consequently, the amount of Mg(OH)2 produced will be based on the 4 moles of KOH, resulting in 2 moles of Mg(OH)2 being formed.
To produce 1 mole of water, you need 2 moles of hydrogen. Therefore, to produce 7.4 moles of water, you would need 2 * 7.4 = 14.8 moles of hydrogen.