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How many H2O can you get from 4 moles of H2 and unlimited O2?
4 moles also 2 moles of oxygen will be consumed
What is the mass of hydrogen gas released from 3.70 g of aluminum metal and hydrochloric acid 2 Al(s) plus 6 HCl(aq) 2 AlCl3(aq) plus 3 H2(g)?
1. Write the balanced equation: 2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g)2. Convert 3.70 g Al to moles of Al: 3.70 g x 1 mol/26.98 g 3. Use stoichiometric ratios in balanced equation to find moles H2 produced: answer from step 2 (moles Al) x 3 moles H2/2 moles Al = moles H2 produced 4. Convert moles H2 produced found in step 3 to grams H2 using molar mass of H2
How many moles of Na are needed to make 4 moles of H2?
It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written
How many moles of NH3 can be produced from 2.37x10-4 moles of H2?
First we are going to find number of H2 moles form it mass H2 moles=(2.37*10^-4)/2 = 1.185*10^-4moles Since 3 moles of H2 makes 2 moles of NH3 then by using this ration, we can find number of moles in NH3 NH3 moles= (2 * 1.185*10^-4)/3 = 0.79*10^-4 moles Finally, we find number of NH3 molecules by multiplying the number of moles with (6.022*10^23). #NH3 molecules = (0.79*10^-4) *(6.022*10^23) =4.75 * 10^19 molecules of NH3 Good luck Enas
How many moles of Al would be produced from 20 moles if Al2O3?
To determine how many moles of aluminum (Al) are produced from 20 moles of aluminum oxide (Al2O3), we need to use the balanced chemical equation for the reduction of Al2O3. The equation is: 2 Al2O3 → 4 Al + 3 O2. From this, we see that 2 moles of Al2O3 produce 4 moles of Al. Therefore, from 20 moles of Al2O3, we can calculate that 20 moles of Al2O3 would produce 40 moles of Al.
How many moles of aluminum are required to produce 4 moles of hydrogen?
This is not a common reaction at standard temperature and pressure.
How many H2O can you get from 4 moles of H2 and unlimited O2?
4 moles also 2 moles of oxygen will be consumed
What is the mass of hydrogen gas released from 3.70 g of aluminum metal and hydrochloric acid 2 Al(s) plus 6 HCl(aq) 2 AlCl3(aq) plus 3 H2(g)?
1. Write the balanced equation: 2Al(s) + 6HCl(aq) ==> 2AlCl3(aq) + 3H2(g)2. Convert 3.70 g Al to moles of Al: 3.70 g x 1 mol/26.98 g 3. Use stoichiometric ratios in balanced equation to find moles H2 produced: answer from step 2 (moles Al) x 3 moles H2/2 moles Al = moles H2 produced 4. Convert moles H2 produced found in step 3 to grams H2 using molar mass of H2
How many moles of water are produced from 373 mol Al?
The balanced chemical equation for the reaction of aluminum (Al) with water (H2O) to produce aluminum oxide (Al2O3) and hydrogen gas (H2) is: 4 Al + 3 H2O → 2 Al2O3 + 3 H2. From the balanced equation, we can see that 3 moles of water are needed for every 4 moles of aluminum reacting. Therefore, if 373 mol of aluminum is reacting, then (373 mol Al) x (3 mol H2O / 4 mol Al) = 279.75 mol of water would be produced.
How many moles of O2 must react with 5 moles of Al?
Sounds like an acid metal reaction to produce hydrogen gas, so I will assume you meant hydrochloric acid. Complete reaction indicates aluminum is limiting and drives the reaction. 2Al + 6HCl --> 2AlCl3 + 3H2 3.0 moles Al (3 moles H2/2 moles Al) = 4.5 mole hydrogen gas produced =========================
How many moles of Na are needed to make 4 moles of H2?
It depends on what you are reacting the sodium with to generate hydrogen gas. The question is incomplete and cannot be answered as it is written
How many moles of NH3 can be produced from 2.37x10-4 moles of H2?
First we are going to find number of H2 moles form it mass H2 moles=(2.37*10^-4)/2 = 1.185*10^-4moles Since 3 moles of H2 makes 2 moles of NH3 then by using this ration, we can find number of moles in NH3 NH3 moles= (2 * 1.185*10^-4)/3 = 0.79*10^-4 moles Finally, we find number of NH3 molecules by multiplying the number of moles with (6.022*10^23). #NH3 molecules = (0.79*10^-4) *(6.022*10^23) =4.75 * 10^19 molecules of NH3 Good luck Enas
How many moles of Al would be produced from 20 moles if Al2O3?
To determine how many moles of aluminum (Al) are produced from 20 moles of aluminum oxide (Al2O3), we need to use the balanced chemical equation for the reduction of Al2O3. The equation is: 2 Al2O3 → 4 Al + 3 O2. From this, we see that 2 moles of Al2O3 produce 4 moles of Al. Therefore, from 20 moles of Al2O3, we can calculate that 20 moles of Al2O3 would produce 40 moles of Al.
What is the mass of 4 moles of hydrogen molecules (H2)?
8.086g
How many moles of aluminum oxide will be produced from 8 moles of Al?
depends on how much aluminum oxide you have, 1gram, 2 billion Kg? how many? cant find the number of moles of oxygen without knowing the mass of the al203
How many moles of aluminum oxide can be made if 5.23 mol Al completely react?
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
In the reaction of aluminum metal and oxygen gas aluminum oxide is formed How many moles of O2 will react with 2.0 moles Al?
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
