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Sounds like an acid metal reaction to produce hydrogen gas, so I will assume you meant hydrochloric acid. Complete reaction indicates aluminum is limiting and drives the reaction.
2Al + 6HCl --> 2AlCl3 + 3H2
3.0 moles Al (3 moles H2/2 moles Al)
= 4.5 mole hydrogen gas produced
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What else can I help you with?
How many moles of H2SO4 will react with 18mol of Al?
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
How many moles of iron oxide are needed to react with 2.5 mol of Al?
The balanced chemical equation for the reaction between iron oxide (Fe2O3) and aluminum (Al) is 2Al + Fe2O3 → Al2O3 + 2Fe. This shows that 2 moles of Al react with 1 mole of Fe2O3. Therefore, 2.5 moles of Al would need 1.25 moles of Fe2O3 to completely react.
How many moles of aluminum oxide can be made if 5.23 mol Al completely react?
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
How many moles of aluminum oxide can be made if 4.0 moles Al completely react?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
What is the molarity of a HCl solution if 2.50 L is needed to react with 12.7 g of Al?
To find the molarity, first calculate the moles of HCl by using the molar mass of Al to convert grams of Al to moles, since HCl and Al react in a 1:1 ratio. Then, divide the moles of HCl by the volume in liters to get the molarity. Molarity = moles of solute / volume of solution in liters.
How many moles of oxygen must react with 4.50 mol Al?
The answer is 3,375 moles oxygen.
How many moles of H2SO4 will react with 18mol of Al?
The balanced chemical equation is: 3H2SO4 + 2Al → Al2(SO4)3 + 3H2. This shows that 3 moles of H2SO4 react with 2 moles of Al. Therefore, using a mole ratio calculation: (18 mol Al) x (3 mol H2SO4 / 2 mol Al) = 27 moles of H2SO4 will react with 18 moles of Al.
In the reaction of aluminum metal and oxygen gas aluminum oxide is formed How many moles of O2 will react with 2.0 moles Al?
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
How many moles of HCl and needed to react 2.4 moles of Al?
Al+HCl===> AlCl3+H2 Is the reaction. You need &.2 moles of HCl.
How many moles of iron oxide are needed to react with 2.5 mol of Al?
The balanced chemical equation for the reaction between iron oxide (Fe2O3) and aluminum (Al) is 2Al + Fe2O3 → Al2O3 + 2Fe. This shows that 2 moles of Al react with 1 mole of Fe2O3. Therefore, 2.5 moles of Al would need 1.25 moles of Fe2O3 to completely react.
How many moles of aluminum oxide can be made if 5.23 mol Al completely react?
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
How many moles of aluminum oxide can be made if 4.0 moles Al completely react?
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
What is the molarity of a HCl solution if 2.50 L is needed to react with 12.7 g of Al?
To find the molarity, first calculate the moles of HCl by using the molar mass of Al to convert grams of Al to moles, since HCl and Al react in a 1:1 ratio. Then, divide the moles of HCl by the volume in liters to get the molarity. Molarity = moles of solute / volume of solution in liters.
What volume of 1.50M HCl is required to neutralize 10g Al OH 3?
10g Al(OH)3 is 0.12821 moles. The moles of hydroxide is thus, 0.38462 moles. If you have 1.5 moles per litre HCl and they react 1:1, you need 256.4ml
How many mole of h2 will be produced from the complete reaction of 20 mole of al?
20 moles of Al will react with water to form 60 moles of H2 and 30 moles of O2, because of the stoichiometry 2:1 in getting H2 en O2 from water, and Al needing an oxidationstate of 3+, so 1 mole is oxidized by 3 moles of H2O.
How many moles of H2 can you get from 4 moles of Al?
This reaction is:2 Al + 2 H2O + 2 NaOH = 2 NaAlO2 + 3 H2From 4 moles of Al 6 moles of hydrogen are obtained.
Calculate the number of moles of hydrogen gas produced when 5.0 moles of aluminum metal react with 5.0 moles of HCl?
Balanced equation first. 2Al + 6HCl >> 2AlCl3 + 3H2 (find limiting reactant ) 5 mole Al (6 mole HCl/2mole Al) = 15 mole HCl 5 mole HCl (2 mole Al/6 mole HCl) = 1.7 mole Al ( Al looks short of what is required, so will drive reaction ) 5 moles Al (3 moles H2/2 moles Al) = 7.5 moles of H2 produced.
