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The answer is 3,375 moles oxygen.

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9y ago

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How many moles of O2 must react with 5 moles of Al?

Sounds like an acid metal reaction to produce hydrogen gas, so I will assume you meant hydrochloric acid. Complete reaction indicates aluminum is limiting and drives the reaction. 2Al + 6HCl --> 2AlCl3 + 3H2 3.0 moles Al (3 moles H2/2 moles Al) = 4.5 mole hydrogen gas produced =========================


How many moles potassium chlorate must be used to produce 6 moles of oxygen gas?

We need 3 moles of potassium perchlorate.


How many moles of potassium chlorate must be used to produce 6 moles if oxygen gas?

Four moles of potassium chlorate are needed.


How many moles no must react to form 4.67 moles no2?

It takes 2 moles of NO to form 2 moles of NO2, so to form 4.67 moles of NO2 you would need 4.67 moles of NO.


How many moles O2 must react with excess H2 to form 7.89 mol H2O?

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How many moles of O2 must react with elemental chlorine to produce 69.1 moles of dichlorine heptoxide?

2Cl2 + 7O2 --> 2Cl2O7So for every 2 moles of dichlorine heptoxide formed, 7 moles of oxygen are reacted.69.1 moles Cl2O7 * (7 moles O2 / 2 moles Cl2O7) = 241.85 moles O2


How many moles of potassium chlorate (KClo3) must be used to produce 6 moles of oxygen?

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How many grams of oxygen are needed to react with 2.5 grams of dihydrogen sulfide?

Sulfur dioxide is SO2, so there are 2 moles of oxygen for each mole of sulfur. In 25 moles of SO2, there are 25 moles of S, so there must be 50 moles of oxygen, or 25 moles of diatomic oxygen gas (O2).


How many moles of potassium chlorate must be used to produce 6 moles of oxygen gas?

2KClO3 --> 2KCl + 3O2For every 3 moles of oxygen gas produced, 2 moles of potassium chlorate are used.6 moles O2 * (2 moles KClO3 reacted / 3 moles O2 produced) = 4 moles KClO3


How many moles of aluminum are needed to react completely with 1.8 mole of FeO?

24 mols of aluminum must have reacted since aluminum oxide is Al2O3


How many moles of cesium chlorate must be decomposed to produce 2.7 moles of oxygen gas?

To find the moles of cesium chlorate needed to produce 2.7 moles of oxygen gas, use the balanced chemical equation for the decomposition of cesium chlorate: 2CsClO3 -> 2CsCl + 3O2 From the equation, it shows that 2 moles of cesium chlorate produce 3 moles of oxygen gas. Therefore, you will need (2/3) * 2.7 = 1.8 moles of cesium chlorate to produce 2.7 moles of oxygen gas.


How many moles of sulfur must be burned to give 0.567 moles of so2?

1 mole of sulfur reacts with 2 moles of oxygen to produce 1 mole of SO2. Therefore, to produce 0.567 moles of SO2, you would need to burn 0.2835 moles of sulfur.