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To determine the amount of iron that can be produced from 119 g of Fe2S3 and 12.7 g of C, we first need to calculate the molar mass of Fe2S3 and C. The molar mass of Fe2S3 is approximately 207.9 g/mol, and the molar mass of C is approximately 12.01 g/mol. Next, we calculate the moles of Fe2S3 and C by dividing the given masses by their respective molar masses. Then, we determine the limiting reactant by comparing the moles of Fe2S3 and C. Finally, we use the stoichiometry of the balanced chemical equation to calculate the theoretical yield of iron, which is approximately 42.4 grams.
You think probable to dinitrogen pentoxide - N2O5.
To determine the mass of ammonia (NH3) that can be produced from 35.0 grams of nitrogen gas (N2), we first need to use the balanced chemical equation for the synthesis of ammonia: N2 + 3H2 → 2NH3. The molar mass of N2 is approximately 28.02 g/mol, allowing us to calculate the number of moles of N2 in 35.0 grams as about 1.25 moles. Since 1 mole of N2 produces 2 moles of NH3, 1.25 moles of N2 will yield 2.5 moles of NH3. The molar mass of NH3 is about 17.03 g/mol, so 2.5 moles of NH3 corresponds to approximately 42.58 grams.
To determine the volume of a solution, you need to know the concentration and the moles of solute. First, calculate the volume using the formula: Volume = moles of solute (6.00 moles) / concentration (2.00 M). This gives you a volume of 3.00 L for the solution made with 6.00 moles of LiF.
To determine the amount of aluminum chloride that can be produced, you need to consider the stoichiometry of the reaction between aluminum and hydrochloric acid. The balanced equation is 2Al + 6HCl → 2AlCl3 + 3H2. From the equation, 2 moles of aluminum produce 2 moles of aluminum chloride. You can use the molar mass of aluminum chloride to convert moles to grams.
Since the ratio of moles of Al to moles of Al2O3 is 4:2, if 5.23 mol Al completely reacts, 2.615 mol Al2O3 can be made.
This is a mole stoichiometry problem. Start with the balanced equation for the synthesis of aluminum oxide: 4Al + 3O2 --> 2Al2O3. The ratio of aluminum to aluminum oxide in this equation is 4:2, or 2:1, so 5.23 moles Al means half that number for Al2O3, so about 2.62 moles of aluminum oxide will be produced.
The balanced chemical equation for the reaction between aluminum (Al) and oxygen (O₂) to form aluminum oxide (Al₂O₃) is: [ 4 \text{ Al} + 3 \text{ O}_2 \rightarrow 2 \text{ Al}_2\text{O}_3 ] According to the balanced equation, 4 moles of aluminum (Al) produce 2 moles of aluminum oxide (Al₂O₃). Therefore, if 4.0 moles of aluminum completely react, it will produce ( \frac{2}{4} \times 4.0 ) moles of aluminum oxide. Calculate that to find the answer.
The stoichiometry of the reaction determines the amount of Mg(OH)2 produced. In this case, the balanced equation shows that 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2. Therefore, if 3 moles of MgCl2 are added, 6 moles of KOH are needed to completely react with it and produce 3 moles of Mg(OH)2.
Ther answer is none! ammonium bromide is made from hydrogen bromide and ammonia NH3 + HBr = NH4Br i mole of each makes 1mole of ammonium salt.
Potassium hydroxide is the limiting agent.
The stoichiometry of the reaction determines the amount of Mg(OH)2 that is formed. From the balanced equation, 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2. Therefore, if 3 moles of MgCl2 are added, based on the ratio in the balanced equation, 1.5 moles of Mg(OH)2 will be produced.
2KClO3 + heat -> 2KCl + 3O2 14 moles KClO3 (3 mole O2/2 mole KClO3) = 21 moles oxygen made This is a common industrial method of producing oxygen.
Sulfur dioxide gas is produced when sulfur reacts with oxygen.
In excess quantity of hydrogen (H2) 5.0 moles water can be formed maximally from 2.5 mole oxygen,because 2.5 x 2 (atoms O per mole oxygen, O2) = 5.0 x 1 (atoms O per mole water, H2O), thus balancing this reaction for oxygen atoms (5 on both sides).
To find the mass of NH3 produced, first calculate the number of moles of NH3 using the given mass and the molar mass of NH3. Then, use the relationship between moles and mass (mass = moles x molar mass) to find the mass of NH3.
When acids react with carbonates, carbon dioxide is produced. You can test this by waiting for the chemical reaction to take place and then using a bung to insert the gas into lime water!