The amount of Koh
Potassium hydroxide is the limiting agent.
2
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
it is base
Inorganic (no carbons)
Potassium hydroxide is the limiting agent.
The answer is one mole.
2
2NaCl + Mg(OH)2 --> MgCl2 + 2NaOH Make sure to put the parentheses around the hydroxide. There is a difference between Mg(OH)2 and MgOH2.
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
These compounds will not react. They both contain the same anion, and thus there can be no reaction between them. Consequently, the reactants will remain unchanged.
it is base
Mg + 2HCl → MgCl₂+ H₂ When a metal reacts with an acid a salt and hydrogen are produced.
Inorganic (no carbons)
Megnesium hydroxide is formed. molecular equation Mg(No3)2 + 2NaOH --> MgOH2 + 2Na(No3) complete ionic. Mg 2+ + (No3)2-2 + 2Na+2 + 2OH-2 --> MgOH2 + 2Na + No3+2 net ionic Mg 2+ + 2OH-2 --> MgOH2
Magnesium hydroxide
about 50% i think