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The stoichiometry of the reaction determines the amount of Mg(OH)2 produced. In this case, the balanced equation shows that 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2. Therefore, if 3 moles of MgCl2 are added, 6 moles of KOH are needed to completely react with it and produce 3 moles of Mg(OH)2.
From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
MgCl2(aq) + 2KOH(aq) --> Mg(OH)2(s) + 2KCl(aq)It is the molar ratio in the equation. Every mole of magnesium chloride requires 2 moles of potassium hydroxide. Thus 3 moles would need 6 moles of alkali for complete reaction. We don't have that much, so potassium hydroxide is the limiting reactant and we can only use 2 moles of the magnesium chloride and produce 2 moles of magnesium hydroxide.
Yes, MgCl2 will react with acid to form magnesium chloride and release hydrogen gas. The reaction can be summarized as: MgCl2 + 2HCl -> MgCl2 + H2↑.
The stoichiometry of the reaction determines the amount of Mg(OH)2 produced. In this case, the balanced equation shows that 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2. Therefore, if 3 moles of MgCl2 are added, 6 moles of KOH are needed to completely react with it and produce 3 moles of Mg(OH)2.
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From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.
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MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)
MgCl2(aq) + 2KOH(aq) --> Mg(OH)2(s) + 2KCl(aq)It is the molar ratio in the equation. Every mole of magnesium chloride requires 2 moles of potassium hydroxide. Thus 3 moles would need 6 moles of alkali for complete reaction. We don't have that much, so potassium hydroxide is the limiting reactant and we can only use 2 moles of the magnesium chloride and produce 2 moles of magnesium hydroxide.
Yes, MgCl2 will react with acid to form magnesium chloride and release hydrogen gas. The reaction can be summarized as: MgCl2 + 2HCl -> MgCl2 + H2↑.
These compounds will not react. They both contain the same anion, and thus there can be no reaction between them. Consequently, the reactants will remain unchanged.
The mole ratio for the given equation is 1:2:1:1. This means for every 1 mole of MgSO4, we need 2 moles of NaCl to react and produce 1 mole of Na2SO4 and 1 mole of MgCl2.
In the reaction 4 moles of aluminum will react with 3 moles of oxygen to form 2 moles of aluminum oxide. Since we have 2.0 moles of aluminum, we would need (2.0 mol Al) x (3 mol O2 / 4 mol Al) = 1.5 moles of O2 to react with it.
Potassium chloride and magnesium nitrate doesn't react.