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From the balanced equation it can be seen that it takes 2 moles KOH to react with each 1 mole of MgCl2. So, the answer is 2.

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In the reaction MgCI2 plus 2KOH MgOH2 plus 2KCI how many moles of MgOH2 are produced for every mole of MgCl2?

The answer is one mole.


In the reaction mgcl2 plus 2koh mgoh2 mgoh2 plus 2kcl if 3 moles mgcl2 are added to 4 moles koh what determined how much mgoh2 is made?

The stoichiometry of the reaction determines the amount of Mg(OH)2 produced. In this case, the balanced equation shows that 1 mole of MgCl2 reacts with 2 moles of KOH to produce 1 mole of Mg(OH)2. Therefore, if 3 moles of MgCl2 are added, 6 moles of KOH are needed to completely react with it and produce 3 moles of Mg(OH)2.


In the reaction mgcl2 plus 2koh mgoh2 plus 2kcl how many moles of koh react with 1 mole of mgcl2?

1 mole of MgCl2 requires 2 moles of KOH to react based on the balanced chemical equation provided.


In the reaction MgCl2 plus 2KOH---MgOH2 plus 2KCl if 3 moles MgCl2 are added to 4 moles 4 KOH what determines how much MgOH2 is made?

Potassium hydroxide is the limiting agent.


In the reaction MgCI2 plus 2KOH Mg(OH)2 plus 2KCI if 6 moles mgci2 are added to 6 moles koh which is the limiting reagent?

MgCl2 would be the limiting reagent


In the reaction MgCl2 plus 2KOH to MgOH2 plus 2KCl how many moles of KOH react with 1 mole of MgCl2?

MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH 2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)


In the reaction mgcl2 plus 2koh mg(oh)2 plus 2kcl How many moles are of mg(oh)2 are produced for every mole of mgcl2?

1


In the reaction MgCl2 plus 2KOH gives magnesium hydroxide plus 2KCl if 3 moles of MgCl2 are added to 4 moles KOH what determines how much magnesium hydroxide is made?

MgCl2(aq) + 2KOH(aq) --> Mg(OH)2(s) + 2KCl(aq)It is the molar ratio in the equation. Every mole of magnesium chloride requires 2 moles of potassium hydroxide. Thus 3 moles would need 6 moles of alkali for complete reaction. We don't have that much, so potassium hydroxide is the limiting reactant and we can only use 2 moles of the magnesium chloride and produce 2 moles of magnesium hydroxide.


In the reaction MgCl2 plus 2KOH---Mg(OH)2 plus 2KCl if 3 moles MgCl2 are added to 4 moles KOH what determines how much Mg(OH)2 is made?

Potassium hydroxide is the limiting reagent.


In the reaction MgCl2 plus 2KOH Mg(OH)2 plus 2KCl if 3 moles MgCl2 are added to 4 moles KOH what determines how much Mg(OH)2 is made?

Potassium hydroxide is the limiting reagent.


In the reaction MgCl2 plus 2KOH-Mg(OH)2 plus 2KCl if 3 moles MgCl2 are added to 4 moles KOH what determines how much Mg(OH)2 is made?

Potassium hydroxide is the limiting reagent.


What volume of hydrogen in L is produced from the complete reaction of 3143 moles of hydrochloric acid at stp Mg s 2HCl aq MgCl2 aq H2 g?

If the chemical reaction is:2 HCl + Mg = MgCl2 + 2 H23143 moles of HCl produce 3143 moles of hydrogenThis volume at 0 0C is70 447,202litres.