In the reaction MgCI2 plus 2KOH Mg(OH)2 plus 2KCI if 6 moles mgci2 are added to 6 moles koh which is the limiting reagent?

Answer 1

MgCl2 would be the limiting reagent

Answer 2

MgCl2

Answer 3

MgCl2 + 2KOH ==> Mg(OH)2 + 2KClLooking at this balanced equation, one sees that every ONE mole of MgCl2 reacts with TWO moles of KOH. Thus, the mole ratio is 1 : 2. Therefore 1 mole MgCl2 is added to 3 moles KOH, there will be plenty of KOH since only 2 moles would be needed. Thus MgCl2 would be limiting.

Answer 4

Write the BALANCED reaction eq'n

2KOH + MgCl2 = 2KCl + Mg(OH)2

So in the molar ratios 2 moles KOH reacts with 1 mole MgCl2

Since we have 6 moles of each

Then 6 moles (KOH) only requires 3 moles MgCl2 ( but we have 6 moles)

So KOH is the limiting reactant leaving 3 moles MgCl2 unreacted,

Answer 5

The limiting reagent is the reactant that is completely consumed in a reaction, which determines the amount of product formed. To determine the limiting reagent, you need to compare the moles of each reactant to their stoichiometric coefficients in the balanced chemical equation. In this case, if you start with 6 moles of both MgCl2 and KOH, MgCl2 would be the limiting reagent because it will be completely consumed first based on the stoichiometry of the reaction.

Answer 6

The limiting reagent is potassium hydroxide.

Answer 7

KOH

Answer 8

MgCl2