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MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH

2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)

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Wiki User

6y ago
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Gretchen Medhurst

Lvl 10
2y ago

MgCl2 + 2KOH ==> Mg(OH)2 + 2KCl1 mole MgCl2 reacts with 2 moles KOH

2 moles KOH x 56.1 g/mole = 112.2 g KOH = 100 g KOH (to 1 significant figure based on 1 mole)

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Wiki User

7y ago

the answer is 2 apex ;)

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Anonymous

Lvl 1
3y ago
the answer is 1 for apex
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Anonymous

Lvl 1
3y ago
ITS 1!
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Anonymous

Lvl 1
3y ago
Its 2 DON'T put 1!!!!!!!!!
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Anonymous

Lvl 1
3y ago
it is 1 for apex 
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Anonymous

Lvl 1
3y ago
It is 2
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Anonymous

Lvl 1
3y ago
It’s 2 Fr don’t pick 1 💀
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Anonymous

Lvl 1
3y ago
It’s (2)(56)g
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GIORDANO SPONSELLER-...

Lvl 1
3y ago
2 is correct don't get trolled
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Anonymous

Lvl 1
3y ago
2 was wrong for me 
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benji

Lvl 1
3y ago
its 2
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benji

Lvl 1
3y ago
its 2
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Kayla Ryder

Lvl 1
3y ago
I got 1
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Krista Payne

Lvl 1
2y ago
It was 2 for me
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Jacob DeHaas

Lvl 1
2y ago
MgCl^2
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Anonymous

Lvl 1
1y ago
I hate you guys so much. It’s 1 On my mom
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Dante Natale

Lvl 1
1y ago
its 1
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Catwd

Lvl 1
1y ago
1
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Ryan Cheng

Lvl 1
10mo ago
IT IS 2 TRUST ME I DID IT ON APEX

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Wiki User

8y ago

The chemical reaction is:
MgCl2 + 2 KOH = Mg(OH)2 + 2 KCl
2 moles of KOH react with 1 mole of MgCl2.

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Wiki User

7y ago


(2)(56 g)

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Wiki User

10y ago

Assuming the reaction is 2KOH + MgCl2 --> 2KCl + Mg(OH)2, and you want both reactants to get used up completely, you must determine how may grams are in 2 moles of potassium hydroxide: KOH = 39+16+1= 56g * 2mol = 112 grams.

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JuJuOnApex

Lvl 5
2y ago

It's 1 for APEX. I just took the test and got it wrong.

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Anonymous

Lvl 1
4y ago

(2)(56 g)

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Anonymous

Lvl 1
3y ago

(2)(56 g)

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Anonymous

Lvl 1
3y ago

apex : 2

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