3(2.6) = 7.8 moles of ions
In the K2SO4 equation, SO4 is not a cation since it consists of negatively charged ions. So K+ is the only cation, and since there are two of them then it is 2 mole K+ per mole K2SO4 . So 2 x 1.55 = 3.10 mol K+
One mole of potassium sulfate, K2SO4, contains 2 moles of potassium (K) ions, 1 mole of sulfur (S) ion, and 4 moles of oxygen (O) atoms.
2.60 moles There are 2 moles of K in K2SO4. the total moles times two (1.3 x 2) is 2.60 moles.
There is one mole of Na⁺ ions for every mole of NaCl. This is because each mole of NaCl dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions in solution.
When HCl dissociates, it produces 1 mole of H+ ions and 1 mole of Cl- ions for every mole of HCl. So, 1 mole of HCl will produce a total of 2 moles of ions (H+ and Cl-).
To find the number of moles of K2SO4 in 15.0 grams, first calculate the molar mass of K2SO4 (K: 39.10 g/mol, S: 32.07 g/mol, O: 16.00 g/mol). Molar mass of K2SO4 = 2(39.10) + 32.07 + 4(16.00) = 174.26 g/mol Now, divide the given mass by the molar mass to find the number of moles: 15.0 g / 174.26 g/mol = 0.086 moles of K2SO4
Since the product, K2SO4 has twice as many potassium atoms as the reactant, KNO3, we may conclude that it takes two moles of reactant to produce one mole of product. The sulfate and nitrate ions will not be the limiting factor.
In the K2SO4 equation, SO4 is not a cation since it consists of negatively charged ions. So K+ is the only cation, and since there are two of them then it is 2 mole K+ per mole K2SO4 . So 2 x 1.55 = 3.10 mol K+
10.0 moles K2SO4 (6.022 X 1023/1 mole K2SO4) = 6.02 X 1024 atoms of potassium sulfate ==========================
One mole of potassium sulfate, K2SO4, contains 2 moles of potassium (K) ions, 1 mole of sulfur (S) ion, and 4 moles of oxygen (O) atoms.
2.60 moles There are 2 moles of K in K2SO4. the total moles times two (1.3 x 2) is 2.60 moles.
There is one mole of Na⁺ ions for every mole of NaCl. This is because each mole of NaCl dissociates into one mole of Na⁺ ions and one mole of Cl⁻ ions in solution.
When HCl dissociates, it produces 1 mole of H+ ions and 1 mole of Cl- ions for every mole of HCl. So, 1 mole of HCl will produce a total of 2 moles of ions (H+ and Cl-).
When Na2CO3 dissociates, it produces 3 moles of ions: 2 moles of Na+ ions and 1 mole of CO3^2- ions. So, if you have 0.5 moles of Na2CO3, you would produce 1.5 moles of ions in total.
Based on the stoichiometry of NaCl, for every one mole of NaCl there is one mole of Na+ and one mole of Cl-. Therefore, there are 1.5 moles Na+ and 1.5 moles Cl-, totaling 3 moles of ions altogether
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
The balanced chemical equation between potassium hydroxide (KOH) and sulfuric acid (H2SO4) is: 2 KOH + H2SO4 -> K2SO4 + 2 H2O This equation shows that 2 moles of KOH react with 1 mole of H2SO4 to produce 1 mole of K2SO4 and 2 moles of water.