I assume that is 28.0 grams.
28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)
= 0.294 moles magnesium chloride
==========================Now,
One mole Mg 2+ = 0.294 moles Mg 2+ ions
=============================
2 moles Cl - = 0.588 moles Cl - ions
=========================
The formula for magnesium chloride is MgCl2. There are one magnesium ion and two chloride ions, for a total of three ions per formula unit.
Three ions are produced: One Mg2+ ion and two Cl- ions.
3 mol
3.27
Two moles
The dissociation of ZnBr2 is: ZnBr2--------- Zn(2+) + 2 Br-
Na2CO32 * 2 = 4 moles sodium.===========================
Dissociation is the decomposition of a substance in ions in a solution.Generally is a decomposition.
This process is called electrolysis. Electrolysis is the process of decomposition of a compound in its molten or aquous state allows electricity to flow through it and in turn gets dissociated into ions.
get the moles of hydrogen ions present in the solution by writing down the acid dissociation formula of the acid. Find the concentration of hydrogen ions present in the solution. Use -log[H+] to get the pH.
1.5 moles
The dissociation of ZnBr2 is: ZnBr2--------- Zn(2+) + 2 Br-
Na2CO32 * 2 = 4 moles sodium.===========================
Ions are obtained by dissociation in water.
Dissociation is the decomposition of a substance in ions in a solution.Generally is a decomposition.
This process is called electrolysis. Electrolysis is the process of decomposition of a compound in its molten or aquous state allows electricity to flow through it and in turn gets dissociated into ions.
Dissociation of what? Table salt, for example (NaCl) dissociates into Na+ and Cl- ions in water.
Dissociation of a base produce hydroxyl ions.
10000
get the moles of hydrogen ions present in the solution by writing down the acid dissociation formula of the acid. Find the concentration of hydrogen ions present in the solution. Use -log[H+] to get the pH.
The Correct Answer is: Ionization and Dissociation.
That would be 2 moles of OH- (hydroxide) ions because there are 2 of them associated with each 1 of the group II metal.