The answer is 9,92 moles.
About 0.88 lbs
To determine the number of moles in 106 grams of MgO, you need to divide the given mass by the molar mass of MgO. The molar mass of MgO is 40.3 g/mol (24.3 g/mol for Mg + 16 g/mol for O). Thus, 106 g / 40.3 g/mol = approximately 2.63 moles of MgO.
12 right?
To determine how much magnesium is needed to yield 12.1g of MgO, we can use the ratio of magnesium to MgO from the initial combustion. From the data provided, 24.3g of magnesium produces 40.3g of MgO. The ratio of magnesium to MgO is 24.3g Mg / 40.3g MgO, which simplifies to approximately 0.603g Mg per gram of MgO. Thus, to yield 12.1g of MgO, we need about 12.1g × 0.603g Mg/g MgO ≈ 7.29g of magnesium.
That is approximately 7/8 of a pound
About 0.88 lbs
1kg = 1000g 400g x 1kg/1000g = 0.400kg
there are two atoms in the chemical MgO
400g = 0.4kg
400g of what?
2kg and 400g
you would get 6.4 mols of NaCl and 0.3 mols of unreacted Na
49.03924
Find how many R's are in 1G (If you divide 4 by 1000 you get .004 per G) Multiply your answer by the G's (400) to get total R's. (.004R x 400G) I get an answer of 400G=1.6R
3kg - 400g is equal to 2.6kg.
2 cups
There are 15 bags of 400g each in 6 kg. You can calculate this by dividing the total weight (6 kg) by the weight of each bag (400g), and then converting the result to bags.