Amount of Br2
= mass of sample / molar mass
= 160 / 2(79.9)
= 1.00mol
One mole of Br2 has 6.023 x 1023 bromine molecules or 2 x 6.023 x 1023 bromine atoms.
.0326 moles
Bromine exists as a diatomic gas. Thus, there are two moles of bromine atoms in 1 mole of bromine gas.
.467 mol of Bromine gas
904,000,000,000,000,000,000,000 (9.04 X 10^23) Bromine atoms.
1,012 mole of bromine for the diatomic molecule.
9 moles of bromine contain 54,2.10e23 molecules.
The number of molecules is approx. 12.10.e+23.
One mole of Br2 has 6.023 x 1023 bromine molecules or 2 x 6.023 x 1023 bromine atoms.
.0326 moles
Bromine at standard temperature has diatomic molecules, and by definition one mole of anything has Avogadro's Number of molecules. Therefore, 2.6 moles of bromine contain 2(exact) X 2.6 X 6.022 X 1023 or 3.1 X 1024 atoms, to the justified number of significant digits.
40*4=160g
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
10,0 moles of bromine atoms contain 60,22140857.1023 atoms.Attention: valid for bromine atoms !.
24.5 mL of a solution 1.0 M bromine contain 0,0245 moles.
Bromine exists as a diatomic gas. Thus, there are two moles of bromine atoms in 1 mole of bromine gas.