Amount of Br2
= mass of sample / molar mass
= 160 / 2(79.9)
= 1.00mol
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
To convert atoms of bromine to moles of bromine, you would need to divide the number of atoms by Avogadro's number (6.022 x 10^23). So, to get moles of bromine, you would divide the number of atoms by Avogadro's number, not multiply.
To determine the number of moles in 2.60100 grams of bromine, we first need to calculate the molar mass of bromine, which is 79.904 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting the values, we get moles = 2.60100 g / 79.904 g/mol = 0.03255 moles of bromine.
Avogadro's constant is 6.02*10^23. This number represents the number of representative particles (atoms, molecules, or formula units) in one mole. To solve your question, we simply multiply Avogadro's constant by the number of moles. 6.02*10^23 * 3.01 = 1.81*10^24
Bromine exists as a diatomic gas. Thus, there are two moles of bromine atoms in 1 mole of bromine gas.
1,012 mole of bromine for the diatomic molecule.
9 moles of bromine contain 54,2.10e23 molecules.
The number of molecules is approx. 12.10.e+23.
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
40*4=160g
Bromine at standard temperature has diatomic molecules, and by definition one mole of anything has Avogadro's Number of molecules. Therefore, 2.6 moles of bromine contain 2(exact) X 2.6 X 6.022 X 1023 or 3.1 X 1024 atoms, to the justified number of significant digits.
To convert atoms of bromine to moles of bromine, you would need to divide the number of atoms by Avogadro's number (6.022 x 10^23). So, to get moles of bromine, you would divide the number of atoms by Avogadro's number, not multiply.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
10,0 moles of bromine atoms contain 60,22140857.1023 atoms.Attention: valid for bromine atoms !.
To determine the number of moles in 2.60100 grams of bromine, we first need to calculate the molar mass of bromine, which is 79.904 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting the values, we get moles = 2.60100 g / 79.904 g/mol = 0.03255 moles of bromine.
24.5 mL of a solution 1.0 M bromine contain 0,0245 moles.