2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
10,0 moles of bromine atoms contain 60,22140857.1023 atoms.Attention: valid for bromine atoms !.
In a sample of phosphorus tribromide (PBr3), each molecule contains three bromine (Br) atoms. Therefore, in 12.9 moles of PBr3, there are ( 12.9 , \text{moles} \times 3 , \text{moles of Br per mole of PBr3} = 38.7 , \text{moles of Br} ). To find the mass of bromine, multiply the number of moles of Br by its molar mass (approximately 79.9 g/mol): ( 38.7 , \text{moles} \times 79.9 , \text{g/g} \approx 3084.63 , \text{grams} ). Thus, there are approximately 3084.63 grams of bromine in the sample.
2,9 moles of bromine is equivalent to 463,4432 g.
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
0,666 moles
10,0 moles of bromine atoms contain 60,22140857.1023 atoms.Attention: valid for bromine atoms !.
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
To determine the number of moles in 2.60100 grams of bromine, we first need to calculate the molar mass of bromine, which is 79.904 g/mol. Then, we use the formula: moles = mass / molar mass. Substituting the values, we get moles = 2.60100 g / 79.904 g/mol = 0.03255 moles of bromine.
To convert atoms of bromine to moles of bromine, you would need to divide the number of atoms by Avogadro's number (6.022 x 10^23). So, to get moles of bromine, you would divide the number of atoms by Avogadro's number, not multiply.
Bromine exists as a diatomic gas. Thus, there are two moles of bromine atoms in 1 mole of bromine gas.
To determine the number of moles of bromine gas in 37.7 grams, you need to divide the given mass by the molar mass of bromine. The molar mass of bromine is approximately 79.904 g/mol. So, 37.7 grams of bromine is equal to 0.471 moles (37.7 g ÷ 79.904 g/mol).
29,56448 (rounded 29,56) grams
To convert grams into atoms, you have to convert them into moles first. Get the molar mass and multiply it by the number of moles to get the atoms.
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
2,9 moles of bromine is equivalent to 463,4432 g.
One molecule of bromine contains 2 atoms. Therefore, to find the number of grams in 602200000000000000000000 atoms, you would divide this number by Avogadro's number (6.022 x 10^23) to get the number of moles, and then convert to grams using the molar mass of bromine (79.9 g/mol).
To find the number of moles in 0.476 grams of bromine, you first need to determine the molar mass of bromine, which is approximately 79.904 g/mol. Then, you can use the formula: moles = mass (g) / molar mass (g/mol). Therefore, in this case, 0.476 grams of bromine is equivalent to 0.006 moles.