.0326 moles
To determine the number of moles of bromine gas in 37.7 grams, you need to divide the given mass by the molar mass of bromine. The molar mass of bromine is approximately 79.904 g/mol. So, 37.7 grams of bromine is equal to 0.471 moles (37.7 g ÷ 79.904 g/mol).
To find the number of moles in 0.476 grams of bromine, you first need to determine the molar mass of bromine, which is approximately 79.904 g/mol. Then, you can use the formula: moles = mass (g) / molar mass (g/mol). Therefore, in this case, 0.476 grams of bromine is equivalent to 0.006 moles.
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
Bromine exists as a diatomic gas. Thus, there are two moles of bromine atoms in 1 mole of bromine gas.
To convert atoms of bromine to moles of bromine, you would need to divide the number of atoms by Avogadro's number (6.022 x 10^23). So, to get moles of bromine, you would divide the number of atoms by Avogadro's number, not multiply.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
2,9 moles of bromine is equivalent to 463,4432 g.
To determine the number of moles of bromine gas in 37.7 grams, you need to divide the given mass by the molar mass of bromine. The molar mass of bromine is approximately 79.904 g/mol. So, 37.7 grams of bromine is equal to 0.471 moles (37.7 g ÷ 79.904 g/mol).
To find the number of moles in 0.476 grams of bromine, you first need to determine the molar mass of bromine, which is approximately 79.904 g/mol. Then, you can use the formula: moles = mass (g) / molar mass (g/mol). Therefore, in this case, 0.476 grams of bromine is equivalent to 0.006 moles.
To find the grams of bromine that react with 15.0g of aluminum, we need to first calculate the molar mass of aluminum and aluminum bromide. Then, find the moles of aluminum reacted using its mass and molar mass. Using the mole ratio from the balanced chemical equation, we can find the moles of bromine that react. Finally, convert the moles of bromine to grams using its molar mass.
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
In a sample of phosphorus tribromide (PBr3), each molecule contains three bromine (Br) atoms. Therefore, in 12.9 moles of PBr3, there are ( 12.9 , \text{moles} \times 3 , \text{moles of Br per mole of PBr3} = 38.7 , \text{moles of Br} ). To find the mass of bromine, multiply the number of moles of Br by its molar mass (approximately 79.9 g/mol): ( 38.7 , \text{moles} \times 79.9 , \text{g/g} \approx 3084.63 , \text{grams} ). Thus, there are approximately 3084.63 grams of bromine in the sample.
There is one mole in approximately 80 grams of bromine (Br). Therefore, in 1 gram of bromine, there would be approximately 1/80 mole, which is equal to 0.0125 moles.
10,0 moles of bromine atoms contain 60,22140857.1023 atoms.Attention: valid for bromine atoms !.
The molar mass of titanium is 47.87 g/mol and the molar mass of bromine is 79.90 g/mol. Titanium reacts with two moles of bromine, so you would need 2 moles of bromine per mole of titanium. Using the molar masses of both elements, you can calculate the grams of bromine needed to react with 22.1 g of titanium.
24.5 mL of a solution 1.0 M bromine contain 0,0245 moles.
16 grams of oxygen how many moles is 0,5 moles.