Taking Avogadro constant to be 6.022 X 1023
The no. corresponds to 1 mol Br atoms = 80 g(Approx)
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
The density of bromine is 3.12 g/ml, therefore 10 ml of bromine would weigh 31.2 grams.
To determine the number of moles of bromine gas in 37.7 grams, you need to divide the given mass by the molar mass of bromine. The molar mass of bromine is approximately 79.904 g/mol. So, 37.7 grams of bromine is equal to 0.471 moles (37.7 g ÷ 79.904 g/mol).
The molar mass of Bromine trifluoride is approximately 126.893 g/mol. Therefore, one mole of Bromine trifluoride contains 126.893 grams.
To find how many grams of sodium carbonate contain 1.773 x 10^17 carbon atoms, you need to consider the molar ratio. Sodium carbonate (Na2CO3) has 1 carbon atom per molecule. Calculate the molar mass of Na2CO3, then use Avogadro's number to convert the number of carbon atoms to moles, and finally to grams.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
1,25 grams of CH4 contain 0,156696.10e23 atoms.
24,163 ng
3,45 grams of H2O contain 1,154.10e23 oxygen atoms.
No, the chemical formula CuBr2 indicates one atom of copper bonding with two atoms of bromine. This means that the molar mass of CuBr2 is not equal to the sum of the molar masses of copper and bromine individually.
6.355 x 10e10 atoms of iron contain 58,93.e-13 grams
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.
the answer to this question is 4.9$ for 100 grams of pure bromine.
The density of bromine is 3.12 g/ml, therefore 10 ml of bromine would weigh 31.2 grams.
The molar mass of sulfur is approximately 32 grams per mole. Therefore, 100 grams of sulfur would contain approximately 3 moles of sulfur atoms (100 grams / 32 grams/mole). To find the number of atoms, you would then multiply the number of moles by Avogadro's number (6.022 x 10^23 atoms/mole) to get the total number of sulfur atoms in 100 grams.
Just about 6.022 X 1023 atoms of sulfur. Sulfur is 32.07 grams per mole.