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How many iron atoms present in 5.0 mol of iron metal?
Five iron atoms have a mass of 1.3155 x 10-22 grams.
If I want one mole of iron atoms how many grams do I need to weigh out?
To obtain one mole of iron atoms, you need to weigh out approximately 55.85 grams of iron. This is because the molar mass of iron (Fe) is about 55.85 grams per mole. Therefore, for one mole, you simply measure out this amount in grams.
How many atoms are in 13.2 grams of iron?
To calculate the number of atoms in 13.2 grams of iron, you first need to determine the molar mass of iron, which is approximately 55.85 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Therefore, there are about 4.49 x 10^22 atoms in 13.2 grams of iron.
How many atoms of iron rusted that weight 63.8 grams?
Rusted iron is FeO, iron oxide. 63.8 grams FeO (1 mole FeO/71.85 grams)(6.022 X 1023/1 mole FeO) = 5.35 X 1023 atoms of iron oxide -------------------------------------------
How many atoms are there in solid iron?
Impossible to answer without knowing a mass or a volume. But I can tell you that there are 6.022x10^23 iron atoms (one mole) for every 55.845 grams of iron. That translates to: 1.078x10^22 iron atoms per gram or given that the density of iron is 7.87 g/cm3 at 25 degrees Celsius... 8.487x10^22 iron atoms per cm3.
How many moles on 738 grams or iron and how many atoms?
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
How many grams of iron are in 6.02 X 1023 atoms of iron?
To calculate the number of grams of iron, you need to convert the number of iron atoms (6.02 x 10^23) into moles by dividing by Avogadro's number (6.022 x 10^23 atoms/mol). Then, multiply the number of moles of iron by the molar mass of iron (55.85 g/mol) to find the grams of iron. This would result in approximately 55.85 grams of iron.
How many iron atoms present in 5.0 mol of iron metal?
Five iron atoms have a mass of 1.3155 x 10-22 grams.
How many atoms are in 13.2 grams of iron?
To calculate the number of atoms in 13.2 grams of iron, you first need to determine the molar mass of iron, which is approximately 55.85 g/mol. Then, you can use Avogadro's number (6.022 x 10^23 atoms/mol) to convert grams to atoms. Therefore, there are about 4.49 x 10^22 atoms in 13.2 grams of iron.
How many atoms of iron rusted that weight 63.8 grams?
Rusted iron is FeO, iron oxide. 63.8 grams FeO (1 mole FeO/71.85 grams)(6.022 X 1023/1 mole FeO) = 5.35 X 1023 atoms of iron oxide -------------------------------------------
How many atoms are found in 600 grams of iron?
To find the number of atoms we need to find number of moles of Fe in 312.0 grams. Molar weight of Fe = 56 Number of moles of Fe in 312 grams = 312/56 =5.571 moles. 1 mole of Fe has Avogadro number of atoms. So 5.571 moles of Fe has atoms = 5.571 * Avogadro number. Avogadro number = 6.022 * 10^23 So total atoms = 5.571 * 6.022 * 10^23 = 33.548 * 10^23 * means multiply, ^ means raised to power.
How many atoms are there in solid iron?
Impossible to answer without knowing a mass or a volume. But I can tell you that there are 6.022x10^23 iron atoms (one mole) for every 55.845 grams of iron. That translates to: 1.078x10^22 iron atoms per gram or given that the density of iron is 7.87 g/cm3 at 25 degrees Celsius... 8.487x10^22 iron atoms per cm3.
How many iron atoms would there be in 169 milligrams of iron?
169 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 10^23/1 mole Fe) = 1.82 X 10^21 atoms of iron --------------------------------------
How many atoms in 10 mg of iron?
10 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 1023/1 mole Fe) = 1.1 X 1020 atoms of iron ===================
There are 10 grams of iron in a sealed container with moist air The sealed container with iron and moist air weighs a total 15 grams what is true after the iron rusts?
After the iron rusts, it will combine with oxygen from the air to form iron oxide. Since the total weight of the sealed container after the iron rusts is still 15 grams, the added weight will be the mass of the oxygen atoms that combined with the iron to form iron oxide.
Which has a greater number of atoms 3 grams of iron or 2 grams of sulfur?
In order to compare the number of atoms, one needs to first convert the masses into moles:3 g Fe x 1 mole/55.8 g = 0.054 moles Fe2 g S x 1 mole/32 g = 0.063 moles STherefore, 2 g of sulfur contains more atoms than does 3 g of Fe. This is because 1 mole of ANY element contains 602x10^23 atoms, so the more moles you have, the more atoms you have.
How many iron atoms are present in 55.845grams of Iron?
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
