That depends. For the most common form of Iron (Iron-56), there are 56 grams.
You may also call 6.02 X 10^23 atoms/molecules a "mole" of atoms/molecules.
The density of iron, Fe, at room temperature is 7.874 g/cm3. So 1cm3 of iron has a mass of 7.874g. 1 mole iron = 55.845g Fe = 6.022 x 1023 atoms Fe. 7.874g Fe x 6.022 x 1023 atoms Fe/55.845g Fe = 8.491 x 1022 atoms Fe
To determine the number of iron atoms in a 23.0 g iron block, you would first calculate the number of moles of iron using the molar mass of iron (55.85 g/mol). Then, you would use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles of iron to atoms.
use the following formula to determine number of moles number of moles = mass given/molar mass (mass on periodic table) one mole = 6.02x10^23 particles (molecules or atoms depending on substance) hence whichever mass has the greatest number of moles has the more atoms
To find the number of moles, you need to divide the number of atoms by Avogadro's number, which is about 6.022 x 10^23 atoms/mol. So, 5.98 x 10^24 atoms of iron would be approximately 9.93 moles of iron.
1 gram H2 (1 mole H2/2.016 grams)(6.022 X 1023/1 mole H2) = 3 X 1023 atoms of hydrogen gas =========================
9,003 x 1023 atoms of iron correspond to 1,495 moles.
Rusted iron is FeO, iron oxide. 63.8 grams FeO (1 mole FeO/71.85 grams)(6.022 X 1023/1 mole FeO) = 5.35 X 1023 atoms of iron oxide -------------------------------------------
The answer is 47,128 x 1023 atoms.
There are 57.6 grams of tin in that sample.
17 grams carbon (1 mole C/12.01 grams)(6.022 X 1023/1 mole C) = 8.5 X 1023 atoms of carbon =====================
10 milligrams iron (1 gram/1000 milligrams)(1 mole Fe/55.85 grams)(6.022 X 1023/1 mole Fe) = 1.1 X 1020 atoms of iron ===================
10 grams nitrogen (1 mole N/14.01 grams)(6.022 X 1023/1 mole N) = 4.3 X 1023 atoms of nitrogen ======================
738 grams iron are equivalent to:- 12,626 moles- 76.10e23 atoms
It depends on the mass of iron. 1 mole Fe = 55.845g = 6.022 x 1023 atoms Fe
Amount of Fe = 55.845/55.845 = 1mol There is 1 mol of Fe in a 55.845g sample. 1 mol of Fe contains 6.02 x 1023 atoms (avogadro constant). Therefore there are 6.02 x 1023 atoms in 55.845g of iron.
Fe, or iron, has a molar mass of 55.845 grams per mole. This means that 0.2 moles is equal to 11.2 grams of iron.
86.0 grams Sn (1 mole Sn/118.7 grams)(6.022 X 1023/1 mole Sn)= 4.36 X 1023 atoms of tin=================