1,012 mole of bromine for the diatomic molecule.
40*4=160g
9 moles of bromine contain 54,2.10e23 molecules.
2,9 moles of bromine is equivalent to 463,4432 g.
To find the number of molecules in 5 moles of Br2, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, the number of molecules in 5 moles of Br2 is calculated as follows: (5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 3.011 \times 10^{24}) molecules. Thus, there are approximately (3.011 \times 10^{24}) molecules of Br2 in 5 moles.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
To find the number of moles in 160g of bromine molecules, we first need to determine the molar mass of bromine which is approximately 79.9 g/mol. Then, we can use the formula: moles = mass / molar mass. Therefore, moles = 160g / 79.9 g/mol ≈ 2 moles.
40*4=160g
To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
2,9 moles of bromine is equivalent to 463,4432 g.
9 moles of bromine contain 54,2.10e23 molecules.
To find the number of molecules in 5 moles of Br2, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, the number of molecules in 5 moles of Br2 is calculated as follows: (5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 3.011 \times 10^{24}) molecules. Thus, there are approximately (3.011 \times 10^{24}) molecules of Br2 in 5 moles.
To find the number of moles in 160g of MgO, you first need to calculate the molar mass of MgO which is 40.3 g/mol for Mg + 16.0 g/mol for O = 56.3 g/mol for MgO. Then, divide the given mass by the molar mass to get the number of moles: 160g / 56.3 g/mol = 2.84 moles of MgO.
To determine the number of moles in 160g of MgO, you first need to calculate the molar mass of MgO, which is 40.3 g/mol for Mg and 16.0 g/mol for O. Adding these together gives a molar mass of 56.3 g/mol for MgO. Next, divide the given mass (160g) by the molar mass of MgO to find the number of moles present. So, 160g / 56.3 g/mol = 2.84 moles of MgO.
1.54 (mol Br2) * 6.022*10+23 (molecule/mol Br2) * 2 (atoms Br/molecule Br2) =1.85*1024 atoms in 1.54 mole Br2
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
The atoms in the reacts are always present in the products. There is one mole of bromine per molecule and .196 moles of the molecule. Thus, there will be .196 mols of bromine present after the reaction.