To find the number of molecules in 5 moles of Br2, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, the number of molecules in 5 moles of Br2 is calculated as follows: (5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 3.011 \times 10^{24}) molecules. Thus, there are approximately (3.011 \times 10^{24}) molecules of Br2 in 5 moles.
9 moles of bromine contain 54,2.10e23 molecules.
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
2,9 moles of bromine is equivalent to 463,4432 g.
1,012 mole of bromine for the diatomic molecule.
2,60x102 grams of bromine (Br) is equal to 1,627 moles Br2.
9 moles of bromine contain 54,2.10e23 molecules.
To calculate the mass of 4.89 x 10^20 molecules of Br2, you need to use the molar mass of Br2, which is 159.808 g/mol. Calculate the number of moles of Br2: 4.89 x 10^20 molecules / 6.022 x 10^23 molecules/mol = 8.13 x 10^-4 moles Use the formula mass = moles x molar mass to find the mass: mass = 8.13 x 10^-4 moles x 159.808 g/mol ≈ 0.130 g
The atoms in the reacts are always present in the products. There is one mole of bromine per molecule and .196 moles of the molecule. Thus, there will be .196 mols of bromine present after the reaction.
If it is 1.54 moles of Br atoms then the answer is 9.274 X 1023 atoms.If it is 1.54 moles of Br2 molecules then the answer is 1.855 X 1024 atoms.
To determine the number of bromine molecules that have a mass equal to 21.8 g, you first need to find the molar mass of Br2, which is 159.808 g/mol. Then, you can use this molar mass to calculate the number of moles in 21.8 g of Br2. Finally, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.
To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
2,9 moles of bromine is equivalent to 463,4432 g.
To determine the number of bromine molecules, you need to first convert the mass of liquid bromine to moles using its molar mass. Then, use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
1,012 mole of bromine for the diatomic molecule.
To determine the number of molecules in 120 grams of bromine gas, you first need to calculate the moles of bromine using its molar mass (molar mass of Br2 = 159.808 g/mol). Then, use Avogadro's number (6.022 x 10^23) to find the number of molecules in that many moles of bromine gas.