A flask contains 0.120mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask
A flask contains 0.410 of liquid bromine, . Determine the number of bromine molecules present in the flask.
2,288.1023 molecules
when asking this question they are looking for the number of Br2 therefore .5 mol .5*6.022*1023 molecules which equals 3.011*1023 molecules
The value 6.022 x 10^23 is called Avogadro's number. So you multiply the amount by this number to determine the molecules..270 X (6.022x10^23) = 1.63 x 10^23
.290 x (6.022 x 10^23) = 1.75 x 10^23
A flask contains 0.410 of liquid bromine, . Determine the number of bromine molecules present in the flask.
2,288.1023 molecules
when asking this question they are looking for the number of Br2 therefore .5 mol .5*6.022*1023 molecules which equals 3.011*1023 molecules
.290 x (6.022 x 10^23) = 1.75 x 10^23
The value 6.022 x 10^23 is called Avogadro's number. So you multiply the amount by this number to determine the molecules..270 X (6.022x10^23) = 1.63 x 10^23
.310 MOLES 6.022*(10^23 ) molecules --------------- times ------------------------------------ = 1.8668 * 10^23 molecules 1 mole because there are 3 sig figs the answer should reflect that number. so the answer is 1.87 * 10^23 molecules
904,000,000,000,000,000,000,000 (9.04 X 10^23) Bromine atoms.
Fullerenes are complex carbon containing molecules.
Bromine in carbon tetrachloride is a brown-colored solution and used as a chemical test. When drops of bromine/carbon tetrachloride are added to a solution containing an unknown compound and the brown-colored bromine solution disappears, that means that the unknown compound contains carbon-carbon double bonds (since it absorbed the bromine solution). On the other hand, if the brown-colored bromine solution doesn't disappear then it means that no carbon double bonds are present. This is called a "Bromine Test."
The atoms in the reacts are always present in the products. There is one mole of bromine per molecule and .196 moles of the molecule. Thus, there will be .196 mols of bromine present after the reaction.
In the formula of any bromoalkane, the sumbol Br symbolizes bromine atom.
Bromine is an element, and no other kinds of atoms or elements are present with it, in a pure sample.