.310 MOLES 6.022*(10^23 ) molecules
--------------- times ------------------------------------ = 1.8668 * 10^23 molecules
1 mole
because there are 3 sig figs the answer should reflect that number. so the answer is 1.87 * 10^23 molecules
A flask contains 0.410 of liquid bromine, . Determine the number of bromine molecules present in the flask.
A flask contains 0.120mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask
2,288.1023 molecules
when asking this question they are looking for the number of Br2 therefore .5 mol .5*6.022*1023 molecules which equals 3.011*1023 molecules
.290 x (6.022 x 10^23) = 1.75 x 10^23
A flask contains 0.410 of liquid bromine, . Determine the number of bromine molecules present in the flask.
A flask contains 0.120mol of liquid bromine, Br2. Determine the number of bromine molecules present in the flask
2,288.1023 molecules
when asking this question they are looking for the number of Br2 therefore .5 mol .5*6.022*1023 molecules which equals 3.011*1023 molecules
.290 x (6.022 x 10^23) = 1.75 x 10^23
The value 6.022 x 10^23 is called Avogadro's number. So you multiply the amount by this number to determine the molecules..270 X (6.022x10^23) = 1.63 x 10^23
904,000,000,000,000,000,000,000 (9.04 X 10^23) Bromine atoms.
Hydrogen and Bromine. Similar to hydrogen chloride it dissolves in water to form hydrobromic acid.
Your question is irrelevant. I think that you were trying to find the number of molecules present in half a mole of water. 1 mole of water contains 6.023 * 1023 number of molecules. Hence half mole contains half of that number of molecules which is 3.0115*1023.
Stratosphere contains the ozone layer. It is present as a pool of ozone molecules.
depends on what salt it is and the purity of the water. if the water is 100% pure , then it contains only hydrogen and oxygen as molecules and if it is common salt then it contains sodium and chlorine as molecules
if you have a water sample that contains either nitrate chloride.