1 mole Br2 = 159.808g Br2 = 6.022 x 1023 molecules Br2
4.89 x 1020 molecules Br2 x 1mol Br2/6.022 x 1023 molecules Br2 x 159.808g Br2/mol Br2 = 0.130g Br2
To determine the number of bromine molecules that have a mass equal to 21.8 g, you first need to find the molar mass of Br2, which is 159.808 g/mol. Then, you can use this molar mass to calculate the number of moles in 21.8 g of Br2. Finally, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.
The molar mass of Br2 is 159.808 g/mol. To convert 3.2 L to grams, you need to use the density of Br2, which is approximately 3.12 g/mL. Then convert grams to kilograms to get the mass in kg, which would be around 10 kg.
Two atoms of sodium are required to react with one molecule of Br2 to form sodium bromide. Therefore, to completely react with 5 molecules of Br2, you would need 10 atoms of sodium.
Among the given molecules, bromine (Br2) has the highest vapor pressure due to its relatively low boiling point and weak intermolecular forces between its molecules. Water (H2O) has a lower vapor pressure compared to bromine because of its stronger hydrogen bonding. Nitrogen trichloride (NCl3) has the lowest vapor pressure since it is a polar molecule with stronger intermolecular forces compared to the other two molecules.
To determine the number of bromine molecules that have a mass equal to 21.8 g, you first need to find the molar mass of Br2, which is 159.808 g/mol. Then, you can use this molar mass to calculate the number of moles in 21.8 g of Br2. Finally, you can use Avogadro's number (6.022 x 10^23) to convert moles to molecules.
To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.
To find the number of molecules in 5 moles of Br2, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, the number of molecules in 5 moles of Br2 is calculated as follows: (5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 3.011 \times 10^{24}) molecules. Thus, there are approximately (3.011 \times 10^{24}) molecules of Br2 in 5 moles.
The mass of 0.030 moles of Br2 is 4.79424 grams, properly rounded to 4.8 grams.
First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.
The chemical formula for bromine when it is a liquid is Br2, indicating that it consists of diatomic molecules.
9.92kg
The molar mass of Br2 is 159.808 g/mol. To convert 3.2 L to grams, you need to use the density of Br2, which is approximately 3.12 g/mL. Then convert grams to kilograms to get the mass in kg, which would be around 10 kg.
The chemical equation for the reaction of acetylene (C2H2) with two molecules of Br2 (bromine) is: C2H2 + 2Br2 → C2H2Br4
because water is highly polar and Br2 is non-polar so the molecules in the water are more attracted to each other. But methylene chloride is non-polar so its molecules are no more strongly attracted to other methylene chloride molecules than they are to Br2 molecules. Since all of the forces are weak, the substance can dissolve.
Br2 is a compound. It is a molecule made up of two atoms of the element bromine bonded together. In its natural state, bromine exists as Br2 molecules, which means it is a compound and not an individual element.
The chemical formula for bromine vapor is Br2, which indicates that bromine exists as diatomic molecules in its gaseous state.