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How many moles of atoms are in 44.0 Br2?
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
What is the mole ratio of Cl2 to Br2 in the given reaction?
The mole ratio of Cl2 to Br2 in the given reaction is 1:1. This means that for every 1 mole of Cl2 that reacts, 1 mole of Br2 is also involved in the reaction.
What is the mass of 4.89 x 1020 molecules of Br2?
To calculate the mass of 4.89 x 10^20 molecules of Br2, you need to use the molar mass of Br2, which is 159.808 g/mol. Calculate the number of moles of Br2: 4.89 x 10^20 molecules / 6.022 x 10^23 molecules/mol = 8.13 x 10^-4 moles Use the formula mass = moles x molar mass to find the mass: mass = 8.13 x 10^-4 moles x 159.808 g/mol ≈ 0.130 g
Which would discolour more Br2 1 mole of ethene or 1 mole of ethyle?
Br2 would discolour more when reacting with 1 mole of ethene compared to 1 mole of ethylbenzene. Ethene, being an alkene, undergoes electrophilic addition with bromine, resulting in the consumption of Br2 and a noticeable colour change. In contrast, ethylbenzene, which is an aromatic compound, does not readily react with Br2 under normal conditions, leading to less or no discolouration. Thus, ethene reacts more readily and causes a greater discolouration of Br2.
How many moles are contained in 44.0 g Br2?
To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.
How much does one mole of bromine weigh?
One mole of bromine (Br2) weighs approximately 159.808 grams.
How many moles of Br2 are there in 160g?
1,012 mole of bromine for the diatomic molecule.
Given the density of Br2 What is the molecular weight?
The molecular weight of a compound is the sum of the atomic weights of all the atoms in a molecule. For bromine (Br2), the density doesn't directly provide information about the molecular weight. The molecular weight of bromine (Br2) is approximately 159.808 g/mol.
How do you calculate the number of moles of bromine present in 16.0ml of Br2 whose density is 3.12gml?
First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.
What is the mass in kg of 3.2L of br2?
9.92kg
What is the mass (in kg) of 3.2 L of Br2?
The molar mass of Br2 is 159.808 g/mol. To convert 3.2 L to grams, you need to use the density of Br2, which is approximately 3.12 g/mL. Then convert grams to kilograms to get the mass in kg, which would be around 10 kg.
How many moles of bromine will be formed upon the complete reaction of 0.248 moles bromine trifluoride?
The complete decomposition reaction is as follows:2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2
