The mass of 0.030 moles of Br2 is 4.79424 grams, properly rounded to 4.8 grams.
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
The mole ratio of Cl2 to Br2 in the given reaction is 1:1. This means that for every 1 mole of Cl2 that reacts, 1 mole of Br2 is also involved in the reaction.
To calculate the mass of 4.89 x 10^20 molecules of Br2, you need to use the molar mass of Br2, which is 159.808 g/mol. Calculate the number of moles of Br2: 4.89 x 10^20 molecules / 6.022 x 10^23 molecules/mol = 8.13 x 10^-4 moles Use the formula mass = moles x molar mass to find the mass: mass = 8.13 x 10^-4 moles x 159.808 g/mol ≈ 0.130 g
To find the number of moles in 44.0 g of Br2, you need to divide the given mass by the molar mass of Br2. The molar mass of Br2 is approximately 159.808 g/mol. Therefore, 44.0 g Br2 is equal to 0.275 moles.
One mole of bromine (Br2) weighs approximately 159.808 grams.
1,012 mole of bromine for the diatomic molecule.
The molecular weight of a compound is the sum of the atomic weights of all the atoms in a molecule. For bromine (Br2), the density doesn't directly provide information about the molecular weight. The molecular weight of bromine (Br2) is approximately 159.808 g/mol.
First convert the volume of the Br2 into grams by using:D=M/VSo we are given that volume=16.0 ml and density=3.12g/ml.M=D*VM=(3.12g/ml)*(16.0ml)=49.92 gThen we use #moles of a substance=#grams present/Formula weight(# of grams of Br2 in 1 mol of Br2)The Formula weight(molar mass) of Br2=2*(79.9 g/mol)=159.80 g/mol Br2#moles of Br2=49.92g/159.80g/mol Br2=.312 moles of Br2 present.
9.92kg
The molar mass of Br2 is 159.808 g/mol. To convert 3.2 L to grams, you need to use the density of Br2, which is approximately 3.12 g/mL. Then convert grams to kilograms to get the mass in kg, which would be around 10 kg.
The complete decomposition reaction is as follows:2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2
To find the number of molecules in 5 moles of Br2, you can use Avogadro's number, which is approximately (6.022 \times 10^{23}) molecules per mole. Therefore, the number of molecules in 5 moles of Br2 is calculated as follows: (5 \text{ moles} \times 6.022 \times 10^{23} \text{ molecules/mole} = 3.011 \times 10^{24}) molecules. Thus, there are approximately (3.011 \times 10^{24}) molecules of Br2 in 5 moles.