The mole ratio of Cl2 to Br2 in the given reaction is 1:1. This means that for every 1 mole of Cl2 that reacts, 1 mole of Br2 is also involved in the reaction.
The complete decomposition reaction is as follows:2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
The balanced chemical equation for the reaction between Br₂ and NaI is: Br₂ + 2NaI -> 2NaBr + I₂ In this reaction, two moles of sodium iodide (NaI) react with one mole of bromine (Br₂) to form two moles of sodium bromide (NaBr) and one mole of iodine (I₂).
The product of the following reaction Cs Br2 is CsBr.
The chemical reaction is:C2H2 + Br2 = CHBr=CHBr
The complete decomposition reaction is as follows:2 BrF3 → Br2 + 3 F2 , so 2 moles BrF3 will give 1 mole Br2 , hence 0.248 mole gives 0.124 mole Br2
44.0 grams Br2 ? 44.0 grams Br2 (1 mole Br2/159.8 grams)(6.022 X 10^23/1 mole Br2)(1 mole Br2 atoms/6.022 X 10^23) = 0.275 moles of Br2 atoms
The compound 2NaCl + Br2 is not a specific compound itself. It represents a chemical reaction where two moles of sodium chloride (NaCl) react with one mole of bromine (Br2). The products of this reaction would be sodium bromide (NaBr) and possibly other byproducts depending on reaction conditions.
The balanced chemical equation for the reaction is: 2Li + Br2 -> 2LiBr. To find the limiting reactant, we convert the given masses to moles, determine the mole ratio from the balanced equation, and compare the actual mole ratio of the reactants to the required mole ratio.
The balanced chemical equation for the reaction between Br₂ and NaI is: Br₂ + 2NaI -> 2NaBr + I₂ In this reaction, two moles of sodium iodide (NaI) react with one mole of bromine (Br₂) to form two moles of sodium bromide (NaBr) and one mole of iodine (I₂).
C8H16 + Br2 -> C8H16Br2
The product of the following reaction Cs Br2 is CsBr.
The reaction between Mg and Br2 results in the formation of MgBr2. The balanced chemical equation is: Mg + Br2 → MgBr2
The reaction you mentioned involves the phase change of bromine from gas (Br2(g)) to liquid (Br2(l)). The standard enthalpy change for this process, represented as ΔH°, is 30.91 kJ/mol, indicating that this amount of energy is released when one mole of bromine gas condenses into a liquid at standard conditions. The value of ΔHf for Br2(g) typically refers to the enthalpy of formation for bromine gas, which is defined as zero since it is the standard state of the element.
The reaction is not possible.
The mass of 0.030 moles of Br2 is 4.79424 grams, properly rounded to 4.8 grams.
No, the reaction Br2 + NaCl → NaBr + Cl2 does not occur. The correct reaction between Br2 and NaCl is 2NaBr + Cl2.