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How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?
Wiki User
∙ 8y ago
The answer is 3,99 moles of carbon dioxide.
Wiki User
∙ 8y ago
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How many moles of CO2 form when 58.0 g of butane C4H10 burn in oxygen?
4 moles
If 5.50 mol of butane are reacted how many moles of water vapor are produced?
Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
How do you find the number of moles that will react with 5 grams of butane?
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
What is the maximum number of moles of carbon dioxide that could be produced when 105 grams of oxygen are reacted with excess of butane C4H10?
Assuming that the reaction is combustion, the balanced reaction equationwould be2 C4H10 +13 O2 ->8 CO2 +10 H2O. This shows that each mole of O2 would produce 8/13 mole of CO2. 105 grams of O2 corresponds to [105/(2 exact)(15.9994)] or about 3.281 moles of O2. or (8/13)(3.281) or 2.02 moles of carbon dioxide, to the justified number of significant digits.
How many moles of oxygen are required to react with 5 moles of butane?
65
How many moles of CO2 form when 58.0 g of butane C4H10 burn in oxygen?
4 moles
How many moles of co2 form when 58.0 g of butane c4h10 burn oxygen?
4 moles
How many grams of oxygen are required to burn 4.8 mol of butane?
The balanced equation for the reaction is 2 C4H10 + 13 O2 -> 8 CO2 + 10 H2O. This shows that 13 moles of diatomic oxygen are required to burn 2 moles of butane. By proportionality, (4.8/2)13 or 31.2 moles of oxygen are required to burn 4.8 moles of butane. This corresponds to 31.2(32) or 1.0 X 103 grams of oxygen.
How many carbon atoms are in 2.00g of butane?
It is hard to pinpoint how many carbon atoms are in 2.5g of butane. Roughly, the answer is 1.04 x 10^23 moles. This had to be indicated by figuring out the moles per grams first.
How many moles of carbon dioxide (CO2) are produced when reacting 6.00 moles of butane (C4H10) in excess oxygen (O2)?
19,5 g butane are needed.
How many moles of co2 form when 58 grams of butane burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
If 5.50 mol of butane are reacted how many moles of water vapor are produced?
Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
What is the mass of water vapor formed when 1g of butane is burned in a lighter?
Balanced equation. 2C4H10 + 13O2 -> 8CO2 +10H2O 8.13 grams C4H10 (1 mole C4H10/58.12 grams)(10 moles H2O/2 mole C4H10)(18.016 grams/1 mole H2O) = 12.6 grams water produced
How much C4H10 would you need to create 20 ml of water in a combustion?
Pure combustion of butane has the reaction 2 C4H10 + 13 O2 equals8 CO2 + 10 H2O. This means that every mole of butane produces 5 moles of water. 20 ml of water equals 1.11 moles, so .222 moles of butane are needed, or 5.17 liters.
How do you find the number of moles that will react with 5 grams of butane?
We need to know the number of moles of WHAT is to react with the butane to provide you with an answer.
What is the mass in grams of 3.00 moles of butane?
Butane is not a element. Butane has a molar mass.
What is the maximum number of moles of carbon dioxide that could be produced when 105 grams of oxygen are reacted with excess of butane C4H10?
Assuming that the reaction is combustion, the balanced reaction equationwould be2 C4H10 +13 O2 ->8 CO2 +10 H2O. This shows that each mole of O2 would produce 8/13 mole of CO2. 105 grams of O2 corresponds to [105/(2 exact)(15.9994)] or about 3.281 moles of O2. or (8/13)(3.281) or 2.02 moles of carbon dioxide, to the justified number of significant digits.
