Each mole of butane, which has formula of C4H10, contains 10 moles of hydrogen atoms. If the butane is completely combusted, all of the hydrogen in the butane is converted in water, with the formula H2O. The amount of water vapor will accordingly be 5.50 X 10/2 = 27.5.
Butane gas is combusted in the presence of Oxygen. For every 2 moles of butane there are obtained 10 moles of water. Therefore from 5.50 moles of butane, it will be obtained 27.5 moles of water.
154 psi
Butane reacts with oxygen to form carbon dioxide and water vapor: 2 C4H10 + 13 O2 → 8 CO2 + 10 H2O If there is insufficient oxygen, combustion may be incomplete and some soot (carbon) or carbon monoxide may be produced.
CO2 + H2 -> CO + H2O one to one here 30.6 moles H2O (1 mole H2/1 mole H2O) = 30.6 moles Hydrogen gas needed
decomposition
Water vapor, carbon dioxide, oxygen, and nitrogen
6 moles COULD be produced
butane
Calculate the mass in grams of water vapor produced if 3.11 moles of propane is burned
Balanced equation. 2C4H10 + 13O2 -> 8CO2 +10H2O 8.13 grams C4H10 (1 mole C4H10/58.12 grams)(10 moles H2O/2 mole C4H10)(18.016 grams/1 mole H2O) = 12.6 grams water produced
Yes
You cannot produce any Iodine from chlorine, because chlorine (Cl2, gas) is an element, hence it does not contain any Iodine (I2, solid with purple vapor). However when 8.00 moles Cl2 react with excess (>16) moles potassium Iodide (KI) then also 8.00 moles of Iodine are produced, not FROM but BY MEANS OF chlorine. Cl2 + 2KI --> 2 KCl + I2
Methane and oxygen react according to the equation:CH4 + 2O2 -->CO2 + 2H2O Thus 1 mole of methane produces 2 moles of water. 25.9 g of water is 25.9/18 moles = 1.44 moles.So we must have started with 0.72 moles of methane, which is 0.72 x 16 g= 11.51 g of methane.
It is produced because of operating fossil fueled power plants that emit carbon oxides, nitrogen oxides, and sulfur oxides. These oxides when get reacted with water vapor in the environment they are converted into acids that fall down with rain.
This reaction?? 2H2O -> 2H2 + O2 this would be one to one and you would get; 174.82 moles of water vapor Without an equation I do not really know what you mean.
The stoichiometric equation is 2H2 + O2 --> 2H2O. From the given amounts, there are .645 moles of H2 and .325 moles of O2. The limiting reactant is H2, so .645 moles of H2O are formed which is equal to 11.6 grams.
Snow is frozen water vapor. It is produced when water vapor in the air is turned solid by the freezing temperature.
That depends on the ambient conditions. The rate at which butane evaporates depends on the ambient pressure, the temperature and the amount of ambient convection. If the butane is very cold, it will take an extremely long time to evaporate. If it is hot, it will pretty much flash into vapor as soon as it is exposed to atmospheric pressure. If it is in the bottom of a long tube where the vapor above the liquid quickly becomes entirely composed of butane, it will evaporate more slowly than if it is just dumped out in a puddle on the ground with a fan blowing over it. Since the vapor pressure of butane is around 2 atmospheres at typical room conditions, it will generally be under pressure in whatever container it is stored in. As soon as the container is opened, it will start boiling. Butane lighters have liquid butane in them because the plastic doesn't have too much trouble containing the relatively low pressure required to keep most of the butane liquid. If you drill a hole in the side of one, the butane will start boiling until all but a bit of residual vapor has escaped.