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Balanced equation.

2C4H10 + 13O2 -> 8CO2 +10H2O

8.13 grams C4H10 (1 mole C4H10/58.12 grams)(10 moles H2O/2 mole C4H10)(18.016 grams/1 mole H2O)

= 12.6 grams water produced

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